C
This is because 10+5=15
15/45=0.3
The Henderson-Hasselbalch approximation is for conjugate acid-base pairs in a buffered solution. We're going to call HA a weak acid, and A- its conjugate base. The equation is as follows:
pH = pKa + log([base]/[acid]), where the brackets imply concentrations
Plugging in our symbols and the pKa value, the equation becomes:
pH = 4.874 + log([A-]/[HA])
Answer:
171 moles of sodium chloride
Explanation:
Number of moles = mass/molar mass
Molar mass of sodium chloride = 58.5 g/mol
mass of sodium chloride = 10 Kg or 10,000 g
Now, to obtain the number of moles of sodium chloride;
Number of moles = 10,000 g/58.5 g/mol
Number of moles = 171 moles of sodium chloride
How many grams of Cu would be needed to react with 2.0 mol HNO3?
<span>by the equation </span>
<span>3Cu + 8HNO3 --> 3Cu(NO3)2 + 2NO + 4H2O </span>
<span>2.0 mol HNO3 reacts with 3/8 ths as many moles of Cu = 0.75 moles of Cu </span>
