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Alex
3 years ago
6

1/5 times 8 =? help please asap

Mathematics
1 answer:
Degger [83]3 years ago
8 0

Answer:

8/5 aka 1.6

Step-by-step explanation:

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Analyze the pre-image ABCD. What are the vertices of the final image if T–1, –2 ◦ ry = x is applied to figure ABCD?
mariarad [96]

Answers:

A''(3, 0); B''(3, 2); C''(1, 1); D''(1, -1)

Explanation:

We perform the reflection across y=x first.  This reflection switches the x- and y-coordinates; this maps:

A(2, 4)→A'(4, 2)

B(4, 4)→B'(4, 4)

C(3, 2)→C'(2, 3)

D(1, 2)→D'(2, 1)

Next we perform the translation.  This translation shifts the figure 1 unit left and 2 units down, by subtracting 1 from the x-coordinate and 2 from the y-coordinate.  This maps:

A'(4, 2)→A''(3, 0)

B'(4, 4)→B''(3, 2)

C'(2, 3)→C''(1, 1)

D'(2, 1)→D''(1, -1)

6 0
3 years ago
Read 2 more answers
How many inches is 11.6 cm
Minchanka [31]
4.567 inches should be the answer
3 0
3 years ago
Read 2 more answers
Histogram or Bar Chart? Select which graphical display is most appropriate to describe the distribution for each of the variable
lara31 [8.8K]

Answer:

a) Bar chart

b) Histogram

c) Bar chart

d) Histogram

Step-by-step explanation:

a) Trash pick-up DAY for each HOUSEHOLD in Ames - This is categorical data because, we are talking about days of the week. For instance, Household 1 might have Sunday as Trash pick-up day and that could be accumulated into frequency. Hence, BAR chart is the most appropriate.

b) Patient WAIT-TIME at ISU. This is continuous (quantitative) data. And the most appropriate is HISTOGRAM.

c) Number of trips taken during a GIVEN SCHOOL YEAR by EACH ISU STUDENT. Let say we have 5 ISU STUDENTS. Student 1 had 5 trips, student 2 had 10 trips, etc.

We want to see which student has the most and least trip in that particular school year. Although is count data but the most appropriate graphical display is BAR chart.

d) TAX BRACKET of ALL Iowa RESIDENTS. This is a continuous (quantitative) data. The most appropriate graphical display is HISTOGRAM.

5 0
3 years ago
Sebastian solved the radical equation y + 1 = but did not check his solution. (y + 1)2 = y2 + 2y + 1 = –2y – 3 y2 + 4y + 4 = 0 (
Softa [21]

Answer:

There are no true solutions to the equation.

Step-by-step explanation:

<u><em>The correct equation is</em></u>

y+1=\sqrt{-2y-3}

Solve for y

squared both sides

(y+1)^2=(-2y-3)

(y^2+2y+1)=(-2y-3)

y^2+2y+1+2y+3=0

y^2+4y+4=0

(y+2)(y+2)=0

y=-2

<em>Verify</em>

substitute the value of y in the original expression

-2+1=\sqrt{-2(-2)-3}

-1=1 ----> is not true

therefore

There are no true solutions to the equation.

4 0
3 years ago
Write the augmented matrix for each system of equations.
Fudgin [204]

<u>We are given the equations: </u>

10x = 10

-5x - 8y = 9

Since we don't have a coefficient of y in the first equation, we will rewrite the first equation as:

10x + 0y = 10

<u>Writing an Augmented matrix for the 2 equations:</u>

10x + 0y = 10

-5x - 8y = 9

\left[\begin{array}{ccc}10&0|&10\\-5&-8|&9\end{array}\right]

5 0
3 years ago
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