Ask question

Ask question

All categories

3 years ago

14

Solve for H.

^{2} h" alt="V= \pi r ^{2} h" align="absmiddle" class="latex-formula">

1 answer:

Alex3 years ago

3 0

I hope this helps you

V=pi.r^2.h

h=V/pi.r^2

You might be interested in

In the diagram, angle LH is parallel angle JK. Find measure H

mario62 [17]

Step-by-step explanation:

for triangle HLM

180-2x

180-(3x+6)

H

2x=3x-10

x=10°

180-36=144°

36-20=16°

H=2x

H= 180-144-16= 20°

8 0

3 years ago

Emmy just bought a new laptop! She used a student discount code that took $50.75 off the original price. The discounted price of

klio [65]

Answer:

can you show the equations?

5 0

3 years ago

Consider the arithmetic sequence below.

kolezko [41]

F(1) is the first term of the arithmetic sequence, then f(1)=-9

Common difference: 7
-2-(-9)=-2+9=7
5-(-2)=5+2=7
12-5=7

Answer: Fourth option
f(1)=-9
Common difference: 7

5 0

3 years ago

Read 2 more answers

I need help fast please

GenaCL600 [577]

Answer:

The answer is 540 mm^3

Step-by-step explanation:

using v= BH

v= 30×18

v= 540mm^3

pls like and follow, hope this helps.:-):-)

3 0

2 years ago

Please help <br> thank you

Scrat [10]

Question 1:

Use the Pythagorean theorem.

If $c^2\ \textless \ a^2+b^2$ , then the angle is acute.
If $c^2=a^2+b^2$ , then the angle is right.
If $c^2\ \textgreater \ a^2+b^2$ , then the angle is obtuse.

$a=18$
$b=80$
$c=81$

$c^2=6561$
$a^2+b^2=324+6400=6724$

$\boxed {c^2\ \textless \ a^2+b^2}$

Thus, the angle is acute.

Question 2:

Take the square root of the area to get the side length.

$\sqrt{200} = \sqrt{100*2} =10 \sqrt{2}$

That's the side length. Since we have a 45-45-90 right triangle if we divide the square across its diagonal, we just multiply the side length by the square root of 2 in order to get the diagonal length.

$10 \sqrt{2} * \sqrt{2}$
$=20$

Your answer is 20 m. Hope this helps! :)

7 0

4 years ago