Question

You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 50 guests. Bratwursts cost $1.25 each and hamburgers $0.95 each. Your budget is $200
let x be the number of bratwursts and y the number of hamburgers. which system of inequalities represents this situation?

Answer 1

Answer:

$x+y\geq 150$

$1.25x+0.95y\leq 200$

Step-by-step explanation:

Let no. of bratwursts be x

Let no. of hamburgers be y

We are given that You want at least three food items for each of the 50 guests.

This means you want at least $3(50) = 150$ bratwursts or hamburgers.

So, equation becomes: $x+y\geq 150$

Now Bratwursts cost $1.25 each

So, Cost of x bratwursts is 1.25 x

Cost of 1 hamburger is $0.95

Cost of y hamburgers = 0.95y

Your budget is $200

So, you cannot afford the bill more than 200

So, equation becomes:$1.25x+0.95y\leq 200$

Hence system of inequalities represents this situation is $x+y\geq 150$ and $1.25x+0.95y\leq 200$

Answer 2

x+y>=120 1.35x+1.2<=175

That's the logical interpretation of this scenario