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choli [55]
3 years ago
9

Match the words with their definitions.

Physics
2 answers:
GREYUIT [131]3 years ago
4 0
<span>a crack across rock layers caused by moving plates
molten rock - fault (a fault is a rupture or scission in a block of rocks that allows both parts from the scission to slide over each other)

</span><span>horizontal intrusion - sill (a sill is a mass of igneous rock that intruded horizontally and laterally through rock layers already existent)

</span><span>vertical intrusion - d(y)ke (a d(y)ke is also a mass of igneous rock, but this time that intruded vertically across rock layers, many times through an already existing crack)

</span><span>natural, upward movement of rock layers - uplift (uplift is a geological process in which a portion of the Earth's crust is elevated from its original position due to plate tectonics)</span>
Gennadij [26K]3 years ago
4 0

the first one on his answer is wroung

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How do you find the kinetic energy of an object? ​
Sergeeva-Olga [200]

Answer:

KE = 1/2 * m * v^{2}

Explanation:

use the formula:

KE = 1/2 * m * v^{2}

KE = kinetic energy in joules (J)

m = mass in kg

v = velocity in m/s

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3 years ago
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When an electric stove element is hot enough, it gives off a dull red glow. When it cools to the point that it no longer glows,
DochEvi [55]

Answer:

It will have a longer wavelength

Explanation:

When an electric stove is hot and gives dull red glow. a part of the energy dissipated is emitted as visible light and part as infrared radiation in the form of heat. When the stove cools down, and no longer glows all the energy is now in the form of infrared radiation.In the electromagnetic spectrum infrared rays have a higher wavelength than visible light. Hence for the reason the radiation will have a higher wavelength since visible light is cut off.

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3 years ago
A ski jumper travels down a slope and
AleksandrR [38]

Answer:

304.86 metres

Explanation:

The x and y cordinates are dcos\theta and dsin\theta respectively

The horizontal distance travelled, x=v_{ox}t=dcos\theta

Making t the subject, t=\frac{dcos\theta}{v_{ox}}

Since y=0.5gt^2=dsin\theta, we substitute t with the above and obtain

0.5g(\frac{dcos\theta}{v_{ox}})^2=dsin\theta

Making d the subject we obtain

d=\frac{2v_{ox}^2sin\theta}{gcos^2\theta}

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3 years ago
Which statement is true of a concave lens?
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3 years ago
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The acceleration due to gravity is 9.81 m/s2, towards the Earth. Rain falling from an altitude of 9,000 m would fall for about 1
Anna [14]

Answer:

the final speed of the rain is 541 m/s.

Explanation:

Given;

acceleration due to gravity, g = 9.81 m/s²

height of fall of the rain, h = 9,000 m

time of the rain fall, t = 1.5 minutes = 90 s

Determine the initial velocity of the rain, as follows;

h = ut + \frac{1}{2} gt^2\\\\9000 = 90u +  \frac{1}{2} (9.8)(90)^2\\\\9000 = 90u + 39690\\\\90u = -30690\\\\u = \frac{-30690}{90} \\\\u = -341 \ m/s

The final speed of the rain is calculated as;

v^2 = u^2 + 2gh\\\\v^2 = (-341)^2 + 2(9.8\times 9000)\\\\v^2 = 292681\\\\v = \sqrt{292681} \\\\v = 541 \ m/s

Therefore, the final speed of the rain is 541 m/s.

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3 years ago
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