Answer:

Now when it will reach at point B then its normal force is just equal to ZERO


Explanation:
Since we need to cross both the loops so least speed at the bottom must be

also by energy conservation this is gained by initial potential energy


so we will have

now we have

here we have
R = 7.5 m
so we have


Now when it will reach at point B then its normal force is just equal to ZERO

now when it reach point C then the speed will be
![mgh - mg(2R_c) = \frac{1}{2]mv_c^2](https://tex.z-dn.net/?f=mgh%20-%20mg%282R_c%29%20%3D%20%5Cfrac%7B1%7D%7B2%5Dmv_c%5E2)


now normal force at point C is given as



White is the cleanliness color
The answer to this is Freon :D
Answer:
Magnetic force, 
Explanation:
It is given that,
Charge, 
Velocity, v = 4.7 m/s
Magnetic field, 

Magnetic force is given by :



So, the magnetic force on this particle is
. Hence, this is the required solution.
We can solve the problem by using the law of conservation of energy:
- at the beginning, all mechanical energy of the object is just kinetic energy:
, where m is the mass and v is the velocity
- at the point of maximum height, all mechanical energy of the object is just gravitational potential energy:
, where h is the maximum height
Therefore, the conservation of energy becomes:

Re-arranging, we find the maximum height:
