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2 years ago

A playground tire swing has a period of 2.0 s on Earth. What is the length of its chain?

Physics

1 answer:

Jet001 [13]2 years ago

5 0

Answer:

Length of the chain, l = 0.99 m

Explanation:

Given that,

A playground tire swing has a period of 2.0 s on Earth i.e.

T = 2 s

We need to find the length of this chain. The relationship between the length and the time period is given by :

$T=2\pi \sqrt{\dfrac{l}{g}}$

Where

l = length of chain

g = acceleration due to gravity

$l=\dfrac{T^2g}{4\pi^2}$

$l=\dfrac{(2)^2\times 9.8}{4\pi^2}$

l = 0.99 meters

So, the length of the chain is 0.99 meters. Hence, this is the required solution.

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2 years ago

A cart of mass 0.8 kg on a horizontal frictionless track has a tension of 4 N applied to on side of the cart. Calculate the acce

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3 years ago

What does the second law of throdynamics state?

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3 years ago

Read 2 more answers

To practice Problem-Solving Strategy 8.1 for circular-motion problems. A cyclist competes in a one-lap race around a flat, circu

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Answer:

Explanation:

distance travelled

s = 2πR

= 2 X 3.14 X 140

= 880 m

final velocity = v

initial velocity = u

distance travelled = s

time = 60 s

s = ut + 1/2 at²

880 = .5 x a x 60²

a = .244 m/s²

final velocity v = at

= .244 x 60

= 14.66

centripetal acceleration at final moment

v² /R

14.66 X 14.66 / 140

= 1.53 m/s⁻²

1.53 m/s²

this is centripetal acceleration which acts towards the centre.

tangential acceleration calculated a _t = .244

redial acceleration ( centripetal ) = 1.53

Resultant acceleration

R²= 1.53² + .244 ²

R = 1.55 m/s²

total force = 1.55 x 76

= 118 N

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2 years ago