how does the graph of displacement versus time look for something moving at a constant positive velocity

Physics

1 answer:

just olya [345]3 years ago

4 0

The answer is: In the graph of displacement versus time, for something moving at a constant positive velocity, the line is straight and is going up. You can see it in the graph attached.

The explanation is shown below:

In a graph of displacement versus time, the displacement is on the y-axis and the time is on the x-axis. This type of graph that represents an object moving at a constant positive velocity, shows a linear function where the lines is straight and goes up (As you can see in the graph attached).

Then, the slope of the line is the velocity of the object and the y-intercept is the initial position.

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(b) Find the position, velocity, and acceleration of the mass at time t = 5π/6.

Juli2301 [7.4K]

Solution
x(t) = 8 cos t, x(5π/6)= 8 cos(5π/6)
cos(5π/6)=cos(3π/6 + 2π/6 )=cos(π/3 +π/2)= - sin π/3 (cos (x+π/2)= -sinx)
x(t) = -8sin π/3 = - 4 .sqrt3
v(t) = -8sint = -8sin (π/3 +π/2)= -8 cosπ/3 (sin (x+π/2)= cosx)
v(t) = -8 cosπ/3 = -8/2= - 4
a(5π/6) = - 8cost = -(- sin π/3)= 4 .sqrt3
a(5π/6) = 4 .sqrt3

4 0

3 years ago

HELP PLS i need this right now

N76 [4]

Answer:

V = 44.4 units.

Explanation:

In order to solve this problem, we must use the Pythagorean theorem. Which is defined by the following expression.

$V = \sqrt{(V_{x})^{2} +(V_{y})^{2} }$