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2 years ago

Write (2 and 4/5) as a percent and then a decimal. please help i don’t understand

Mathematics

1 answer:

worty [1.4K]2 years ago

6 0

Percent is 480% and the decimal is 2.8

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The new figure after a transformation is performed is called the __________.

Luda [366]

we know that

A figure before the transformation is called pre-image and the figure after a transformation is called image

therefore

<u>the answer is the option D</u>

Image

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3 years ago

Read 2 more answers

What set of transformations is performed on triangle RST to form triangle R’S’T’?

ra1l [238]

Answer:

D. A translation 2 units down followed by a 270-degree counterclockwise rotation about the origin

Step-by-step explanation:

The given triangle has vertices at R(3,4), S(1,1), and T(5,1)

Translating the the vertices down by 2 units, we apply the rule;

$(x,y)\to (x,y-2)$

$\implies (3,4)\to (3,2)$

$\implies (1,1)\to (1,-1)$

$\implies (5,1)\to (5,-1)$

Rotating the resulting vertices through an angle 270 degrees counterclockwise, we apply the rule:

$(x,y)\to (x,-y)$

$\implies (3,2)\to R'(2,-3)$

$\implies (1,-1)\to S'(-1,-1)$

$\implies (5,-1)\to T'(-1,-5)$

Therefore the correct choice is D.

4 0

3 years ago

The table below shows the results of a screening program organized by Level 300 students of the department physiotherapy of the

Vladimir [108]

The correct answer is C because they are asking for the specific screening kit marks

7 0

2 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

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3 years ago

The living room in a new house has the dimensions shown. What is the volume of the room?

Savatey [412]

Add the sides then what ever you got add that up with 9 yd

5 0

3 years ago