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pashok25 [27]
3 years ago
10

Help please urgenttt

Mathematics
1 answer:
stiv31 [10]3 years ago
3 0

Answer:

its a

Step-by-step explanation:

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36=9x................//................................
slega [8]

36=9x

(divide both sides by nine)

4= x

8 0
3 years ago
Solve each exponential equation by using properties of common logarithms. When necessary, round answers to the nearest hundredth
lisabon 2012 [21]

Answer:

0.08

Step-by-step explanation:

Please use parentheses to indicate which operations must be done first.  I 'm choosing to believe that you meant 7^(3x-1) and 5^(x-1).

Taking the common log of both sides, we get:

(3x-1)log 7 = (x-1)log 5

Then 3x·log 7 - log 7 = x log 5 - log 5

Grouping the x terms:

x(3·log 7 - log 5) = log 7 - log 5.  We combine log 7 and log 5, obtaining log (7/5).

Then x(3·log 7 - log 5) = log (7/5).

Solving for x:

      log (7/5)

x = ---------------------

      3·log 7 - log 5

        0.1461

x   = ------------- = 0.08

         1.0363

This agrees with the 3rd answer choice.

7 0
3 years ago
If a adult ticket is 5$ and a student ticket is 1$ the total money collected is 2,662 and the sold ticket is 1,198
PIT_PIT [208]
5a + s = 2662
a + s = 1198
4a = 1464
a = 366

5(366) + s = 2,662
1830 adult tickets sold

2662 - 1830 = 832
832 student tickets sold
4 0
3 years ago
PLS HELP ME FAST PLS !!!!!!!!!!!
erastova [34]

Answer:

The Answer is P = (-2.5 , 1 )

Step-by-step explanation:

Let, the point is P(x,y)

then, x=\frac{m_{1}x_{2}+ m_{2}x_{1}}{m_{1}+m_{2}}

     =>x=\frac{5*(-1)+ 3*(-5)}{5+3}

     ∴x=-2.5

Again, y=\frac{m_{1}y_{2}+ m_{2}y_{1}}{m_{1}+m_{2}}

     =>y=\frac{5*7+ 3*(-9)}{5+3}

     ∴y=1

Thus, P = (-2.5 , 1 )

6 0
3 years ago
If f(x) = 1 – x, which value is equivalent to |f(i)|?l
LenaWriter [7]

Answer:

Square root ( 2 )

Step-by-step explanation:

We have to determine which value is equivalent to | f ( i ) | if the function is: f ( x ) = 1 - x. We know that for the complex number: z = a + b i , the absolute value is: | z | = sqrt( a^2 + b^2 ). In this case: | f ( i )| = | 1 - i |. So: a = 1, b = - 1. | f ( i ) | = sqrt ( 1^2 + ( - 1 )^2) = sqrt ( 1 + 1 ) = sqrt ( 2 ).  

3 0
4 years ago
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