Question

A sample of a gas originally at 29 °c and 1.25 atm pressure in a 3.0 l container is allowed to contract until the volume is 2.2 l and the temperature is 11 °c. the final pressure of the gas is ________ atm.

Answer 1

Answer: 1.6 atm. pV/T = constant. (1.25 * 3.0)/(273+29) <-- work in Kelvin This gives you the constant. Then you want p So p = (T*constant)/V = (284*0.0124)/2.2 I get = 1.6atm