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bulgar [2K]
3 years ago
12

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

litter and gasoline. Which of the following describe how these items would need to separated from the water? Why?
Both gasoline and litter would need to be chemically separated from the water, because both form new bonds with the water.


Litter would need to be physically separated with water and gasoline would need to be chemically separated from water, because both form a mixture with the water.


Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.


Both gasoline and litter would need to be chemically separated from the water, because neither bonds with the water.
Chemistry
2 answers:
ddd [48]3 years ago
8 0

Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.


kari74 [83]3 years ago
6 0

actually the correct answer is d I took the quiz and got an a so I'm pretty sure :)

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Which of the following statements correctly explains why bromination reactions are more selective than chlorination reactions.
Vinvika [58]

Answer: A bromine radical is more stable than chlorine radical, so it is less reactive and more choosy.

Explanation:

A chlorine atom being more electronegative in nature is able to attract a hydrogen atom more readily towards itself as compared to a bromine atom.

Since bromine is less electronegative in nature so bromine will be more selective as a hydrogen abstracting agent. As a result, bromine radical is more stable in nature than chlorine radical.

Thus, we can conclude that bromine radical is more stable than chlorine radical, so it is less reactive and more choosy.

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8 0
3 years ago
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Liono4ka [1.6K]
A is the right answer
6 0
3 years ago
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Calculate the enthalpy for this reaction: 2C(s) + H2(g) ---&gt; C2H2(g) ΔH° = ??? kJ Given the following thermochemical equation
nordsb [41]

Answer:

The enthalpy for given reaction is 232 kilo Joules.

Explanation:

C_2H_2(g) + \frac{5}{2}O_2(g)\rightarrow 2CO_2(g) + H_2O(l), \Delta H^o_{1} = -1,123 kJ...[1]

C(s) + O_2(g)\rightarrow CO2(g), \Delta H^o_{2} = -340 kJ..[2]

H_2(g) + \frac{1}{2}O_2(g)\rightarrow H_2O(l) ,\Delta H^o_{3} = -211 kJ..[3]

2C(s) + H_2(g)\rightarrow C_2H_2(g),\Delta H^o_{4} =?..[4]

2 × [2] + [3] - [1] ( Using Hess's law)

\Delta H^o_{4}=2\times \Delta H^o_{2}+\Delta H^o_{3} - \Delta H^o_{1}

\Delta H^o_{4}=2\times (-340 kJ) + (-211 kJ) - (-1,123 kJ)

\Delta H^o_{4}=232 kJ

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5 0
3 years ago
Write the ions present in solution of k2co3. express your answers as chemical formulas separated by a comma. identify all of the
GarryVolchara [31]

Answer : The ions present in the solution of K_2CO_3 are K^+ and CO^{2-}_3 in aqueous state.

Explanation :

When K_2CO_3 is in aqueous solution then they dissociates into their ions.

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Therefore, the ions present in solution of K_2CO_3 are K^+ and [tex]CO^{2-}_3[tex] in aqueous state.

8 0
3 years ago
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