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bulgar [2K]
3 years ago
12

When cleaning up a local beach, students found many different particles that were in the water that affected the shoreline, like

litter and gasoline. Which of the following describe how these items would need to separated from the water? Why?
Both gasoline and litter would need to be chemically separated from the water, because both form new bonds with the water.


Litter would need to be physically separated with water and gasoline would need to be chemically separated from water, because both form a mixture with the water.


Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.


Both gasoline and litter would need to be chemically separated from the water, because neither bonds with the water.
Chemistry
2 answers:
ddd [48]3 years ago
8 0

Your answer is C. Both gasoline and litter would need to be physically separated from the water, because neither bonds with the water.


kari74 [83]3 years ago
6 0

actually the correct answer is d I took the quiz and got an a so I'm pretty sure :)

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Answer:

True.

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When a radioactive sample decays for 2 half-lives the amount remaining will be ____ of the original?
mash [69]
1/4 of the original.
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6. How many moles are in 25g of potassium?
Ahat [919]
0.6394139898665671 that’s how many moles are in 25g of potassium !
8 0
3 years ago
What’s the answer ?
Romashka-Z-Leto [24]

Answer:

45.3°C

Explanation:

Step 1:

Data obtained from the question.

Initial pressure (P1) = 82KPa

Initial temperature (T1) = 26°C

Final pressure (P2) = 87.3KPa.

Final temperature (T2) =.?

Step 2:

Conversion of celsius temperature to Kelvin temperature.

This is illustrated below:

T(K) = T(°C) + 273

Initial temperature (T1) = 26°C

Initial temperature (T1) = 26°C + 273 = 299K.

Step 3:

Determination of the new temperature of the gas. This can be obtained as follow:

P1/T1 = P2/T2

82/299 = 87.3/T2

Cross multiply to express in linear form

82 x T2 = 299 x 87.3

Divide both side by 82

T2 = (299 x 87.3) /82

T2 = 318.3K

Step 4:

Conversion of 318.3K to celsius temperature. This is illustrated below:

T(°C) = T(K) – 273

T(K) = 318.3K

T(°C) = 318.3 – 273

T(°C) = 45.3°C.

Therefore, the new temperature of the gas in th tire is 45.3°C

6 0
3 years ago
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