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Delicious77 [7]
3 years ago
15

PLZ help me

Chemistry
1 answer:
Alona [7]3 years ago
5 0

Answer:

Wavelength in high frequency waves:

Wavelength. Waves of blue light have a shorter wavelength than waves of red light. The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength.

Wavelength in low frequency waves:

The frequency of a wave is inversely proportional to its wavelength. That means that waves with a high frequency have a short wavelength, while waves with a low frequency have a longer wavelength. Light waves have very, very short wavelengths.

Explanation:

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Omg I’ve been stressing for the past minutes can someone please help me
Alona [7]

Answer:

I think it would be the last answer

Explanation:

5 0
3 years ago
Read 2 more answers
A cylinder and piston assembly (defined as the system) is warmed by an external flame. The contents of the cylinder expand, doin
melomori [17]

Answer:

ΔE = 73 J

Explanation:

By the first law of thermodynamics, the energy in the system must conserved:

ΔE = Q - W

Where ΔE is the internal energy, Q is the heat flow (positive if it's absorbed by the system, and negative if the system loses heat), and W is the work (positive if the system is expanding, and negative if the system is compressing).

So, Q = + 551 J, and W = + 478 J

ΔE = 551 - 478

ΔE = 73 J

3 0
3 years ago
2. What is the average height in cm for plants in group 2? * 38 cm 56 cm 97 cm 114 cm
Nina [5.8K]

Answer:

76.25cm

Explanation:

38cm + 56cm +97cm +114cm = 305cm

305cm÷4 = 76.25cm

6 0
3 years ago
How many moles of ca(oh)2 are in 25ml of 1.5 M solution?
Klio2033 [76]
Molar concentration is

C=\frac{\eta}{V}

[V]=Liters

[\eta]=mol

\eta=C*V

V=25~mL=0.025~L

\eta=1.5*0.025

\boxed{\boxed{\eta=0.0375~moles}}
6 0
4 years ago
The equilibrium constant is given for two of the reactions below. Determine the value of the missing equilibrium constant. 2A(g)
monitta

Answer:

The value of the missing equilibrium constant ( of the first equation) is 1.72

Explanation:

First equation: 2A + B ↔ A2B   Kc = TO BE DETERMINED

 ⇒ The equilibrium expression for this equation is written as: [A2B]/[A]²[B]

Second equation: A2B + B ↔ A2B2   Kc= 16.4

⇒ The equilibrium expression is written as: [A2B2]/[A2B][B]

Third equation:  2A + 2B ↔ A2B2     Kc = 28.2

⇒ The equilibrium expression is written as: [A2B2]/ [A]²[B]²

If we add the first to the second equation

2A + B + B ↔ A2B2   the equilibrium constant Kc will be X(16.4)

But the sum of these 2 equations, is the same as the third equation ( 2A + 2B ↔ A2B2)   with Kc = 28.2

So this means: 28.2 = X(16.4)

or X = 28.2/16.4

X = 1.72

with X = Kc of the first equation

The value of the missing equilibrium constant ( of the first equation) is 1.72

7 0
3 years ago
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