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2 years ago

Genetic mutations are

Chemistry

2 answers:

charle [14.2K]2 years ago

6 0

C. Sometimes
they can have various benefits but some genetic mutations can cause disadvantages

Gnoma [55]2 years ago

3 0

Answer:

c. sometimes

Explanation:

Its depending on what the new genetic sequence expresses.

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A flask contains an equal mixture of oxygen and argon. Which of the following statements is true about the effusion of the gases

frozen [14]

Given that the pressure, temperature and area of effusion is constant, the rate of effusion is inversely proportional to the square root of the molecular mass of the gas.
Mr Oxygen = 32
Mr Argon = 40
Effusion Oxygen = 1/√32
Effusion Argon = 1/√40
Effusion Oxygen / Effusion Argon = √(40) / √(32)
=√(40/32) = √(5/4) = 1.19
Thus, Oxygen will effuse 1.19 times faster than Argon. The second option is correct.

8 0

3 years ago

This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water.

ryzh [129]

Complete Question:

This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water. Using the formula V M D = , what is the density of the marble?

(See attachment for full diagram)

Answer:

1.27 g/cm³

Explanation:

First, find the volume of rock:

Volume of rock = volume of water after rock was placed - volume of water before rock was placed

Volume of rock = 13 - 10 = 3ml

Density of rock = grams of rock per 1 cm³

Note: 1 ml = 1 cm³

Let x represent amount of rock per 1 cm³

Thus,

3.8g = 3 cm³

x = 1 cm³

Cross multiply

1*3.8 = 3*x

3.8 = 3x

3.8/3 = 3x/3

1.27 = x

Density of rock = 1.27 g/cm³

3 0

3 years ago

Help plzz pick on the picture

Oksanka [162]

The answer to this question would most definitely be the last one

8 0

3 years ago

Liquid octane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 63. g of octane is mi

Sever21 [200]

Answer:

52.1 g is the maximum mass of CO₂, that can be produced by this combustion

Explanation:

Mass of Octane: 63 g

Mass of O₂: 59.4 g

This is a combustion reaction where the products, are always water and CO₂. We define the equation:

2C₈H₁₈ (l) + 25O₂(g) → 16CO₂(g) + 18H₂O(g)

As we have, both mases of each reactant, we must define which is the limiting reagent. We convert the mass to moles:

63 g. 1mol / 114g = 0.552 moles

59.4 g . 1mol / 32g = 1.85 moles

Certainly, the limiting reagent is the oxygen:

2 moles of octane need 25 moles of O₂ to react

Therefore, 0.552 moles of octane must need (0.552 . 25) /2 = 6.9 moles of O₂ (I do not have enough moles of oxygen, I need 6.9 and I only got 1.85 moles)

When we know the limiting reagent we can do the calculations with the stoichiometry of the reaction:

25 moles of O₂ can produce 16 moles of CO₂

Therefore, 1.85 moles of O₂ may produce (1.85 . 16) /25 = 1.18 moles.

We convert the moles to mass to get the final answer:

1.18 mol . 44 g / 1mol = 52.1 g

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3 years ago

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Yuliya22 [10]

1.C 2.D 3.B is the correct answer i think

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3 years ago

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