The only factoring you need to do is already done for you:
<em>x</em>² + <em>x</em> - 12 = (<em>x</em> + 4) (<em>x</em> - 3)
What you're asked to do is decompose
(3<em>x</em> - 4) / (<em>x</em>² + <em>x</em> - 12)
into partial fractions, i.e. find <em>a</em> and <em>b</em> such that
(3<em>x</em> - 4) / (<em>x</em>² + <em>x</em> - 12) = <em>a</em> / (<em>x</em> + 4) + <em>b</em> / (<em>x</em> - 3)
Multiply both sides by <em>x</em>² + <em>x</em> - 12 :
3<em>x</em> - 4 = <em>a</em> (<em>x</em> - 3) + <em>b</em> (<em>x</em> + 4)
3<em>x</em> - 4 = (<em>a</em> + <em>b</em>) <em>x</em> + (-3<em>a</em> + 4<em>b</em>)
So we have
<em>a</em> + <em>b</em> = 3
-3<em>a</em> + 4<em>b</em> = -4
and solving this system gives
<em>a</em> = 16/7 and <em>b</em> = 5/7
so you should submit the numbers in bold:
(3<em>x</em> - 4) / (<em>x</em>² + <em>x</em> - 12) = 16 / (7 (<em>x</em> + 4)) + 5 / (7 (<em>x</em> - 3))
Answer: 20
Step-by-step explanation: see screenshot
Answer:
the quotient is 6x^2 - 16x + 16, and the remainder is just 4
Step-by-step explanation:
The polynomial 6x^3-10x^2+20 has coefficients {6, -10, 0, 20}. Division by the binomial x + 1 requires that we use -1 as the divisor. The synthetic division setup becomes:
-1 / 6 -10 0 20
-6 16 -16
-----------------------------
6 -16 16 4
Taking the coefficients {6, -16, 16}, we write the quotient as
6x^2 - 16x + 16, and the remainder as just 4.
Answer:
Step-by-step explanation:
Answer:
0.92
Step-by-step explanation:
