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tino4ka555 [31]
3 years ago
15

23.) What is one benefit or drawback to an hourly wage?

Mathematics
1 answer:
xxMikexx [17]3 years ago
6 0
An hourly wage may result in lower pay
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What is a real life example of trigonometric ratios
Brut [27]

Answer:

Trigonometry can be used to measure the height of a building or mountains

Step-by-step explanation:

if you know the distance from where you observe the building and the angle of elevation you can easily find the height of the building. Similarly, if you have the value of one side and the angle of depression from the top of the building you can find and another side in the triangle, all you need to know is one side and angle of the triangle.

3 0
3 years ago
A ball is thrown from a height of 70 meters with an initial downward velocity of 10/ms. The ball's height h (in meters) after t
dmitriy555 [2]

Answer:h=−5t2−10t+70

Step-by-step explanation:

<!>BRAINLIEST APPERICATED<!> :D

3 0
3 years ago
‼️‼️help please ASAP ‼️
Snezhnost [94]
Its A or 6 because 30 divided by 5 is 6
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Donna is running a track it takes her 10 minutes to run 6 laps if she keeps running at the same speed how long will it take her
kaheart [24]
To solve this problem we can make a proportion.
6      5
-- = ---
10    x

to solve this proportion we can cross multiply and divide.
5 times 10 is 50.  divided by 6 is 8.3
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7 0
3 years ago
Read 2 more answers
A ball is thrown in the air from a height of 3 m with an initial velocity of 12 m/s. To the nearest tenth of a second, how long
stepladder [879]

Answer:  1.4 seconds

<u>Step-by-step explanation:</u>

The equation is: h(t) = at² + v₀t + h₀          where

  • a is the acceleration (in this case it is gravity)
  • v₀ is the initial velocity
  • h₀ is the initial height

Given:  

  • a = -9.81 (if it wasn't given in your textbook, you can look it up)
  • v₀ = 12
  • h₀ = 3

Since we are trying to find out when it lands on the ground, h(t) = 0

EQUATION:   0 = 9.81t² + 12t + 3

Use the quadratic equation to find the x-intercepts

                        a=-9.81, b=12, c=3

x=\dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\\x=\dfrac{-(12)\pm \sqrt{(12)^2-4(-9.81)(3)}}{2(-9.81)}\\\\\\x=\dfrac{-12\pm 16.2}{-19.62}\\\\\\x=\dfrac{-12+ 16.2}{-19.62}=-0.2\qquad x=\dfrac{-12- 16.2}{-19.62}=\large\boxed{1.4}\\

Note: Negative time (-0.2) is not valid

4 0
3 years ago
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