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yarga [219]
3 years ago
10

On a road trip, Sara’s brother drove 47.5% of the trip, and Sara drove 80% of the remainder. If Sara drove for 4 hours and 12 mi

nutes, how long was the road trip?
Mathematics
1 answer:
Ber [7]3 years ago
3 0
Sara's brother drove 47.5% of the trip, and didn't for the rest of the 52.5%
Sara drove 80% of the remainder of what her brother's drove, so she drove 80% of the 52.5%. To know how much she drove from the total trip, we multiply 80% by 52.5%. Remember that the percentage is a fraction over 100.
80% * 52.5% = (80/100) * (52.5/100) = 4200/10000 = 0.42
Then to transform it to a percentage, we multiply the answer by 100 and get 42. So Sara drove 42% of the trip.
Let x by the duration of the whole trip, and let's use the rule of three:
4 hours and 12 minutes = 4*60 + 12 = 240 + 12 = 252 minutes.

42% --> 252 minutes
100% --> x

x = (100*252)/42 = 600 minutes.

600 minutes --> 10 hours.

So the trip last 10 hours.

Hope this Helps! :)
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