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defon
3 years ago
7

A nucleus of mass number 81 contains 46 neutrons. an atomic ion of this element has 36 electrons in it. write the symbol for thi

s atomic ion (give the symbol for the nucleus and give the ionic charge as a right superscript).
Chemistry
1 answer:
nasty-shy [4]3 years ago
8 0

A nucleus of mass number 81 contains 46 neutrons

Mass number=number of protons+number of neutrons

81=number of protons+ 46

number of protons=81-46

number of protons=35

In an atom, number of electrons=number of protons=35

So, the element is ⁸¹Br₃₅ .

Atomic ion of Br, having 36 electrons in it will be:

                                                                                      ⁸¹Br⁻₃₆

The symbol for this atomic ion will be Br and charge on the ion will be -ve.



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Randy is building a house. He wants to put stucco on the outside walls of his house. To make stucco, he needs sand. He lives on
allochka39001 [22]

Answer:

(c)-He separates the larger pebbles and other debris from the finer sand by sifting it with wire mesh.

Explanation:

A mixture is an association of substances that not react between them. It can be homogeneous when it's not possible to see the substances, or heterogeneous when it's possible to see each the substances.

Randy separates the substances of the soil with a wire mesh, so it's possible to define the substances, then the mixture is heterogeneous.

8 0
4 years ago
A) Calculate the standard free-energy change at 25 ∘C for the following reaction:
Genrish500 [490]

Answer:

A) ΔG° = -3,80x10⁵ kJ

B) E° = 2,85V

Explanation:

A) It is possible to answer this problem using the standard ΔG's of formation. For the reaction:

Mg(s) + Fe²⁺(aq) → Mg²⁺(aq) + Fe(s)

The ΔG° of reaction is:

ΔG° = ΔGFe(s) + ΔGMg²⁺(aq) - (ΔGFe²⁺(aq) + ΔGMg(s) <em>(1)</em>

Where:

ΔGFe(s): 0kJ

ΔGMg²⁺(aq): -458,8 kJ

ΔGFe²⁺(aq): -78,9 kJ

ΔGMg(s): 0kJ

Replacing in (1):

ΔG° = 0kJ -458,8kJ - (-78,9kJ + okJ)

<em>ΔG° = -3,80x10² kJ ≡ -3,80x10⁵ kJ</em>

B) For the reaction:

X(s) + 2Y⁺(aq) → X²⁺(aq) + 2Y(s)

ΔG° = ΔH° - (T×ΔS°)

ΔG° = -629000J  - (298,15K×-263J/K)

ΔG° = -550587J

As ΔG° = - n×F×E⁰

Where n are electrons involved in the reaction (<em>2mol</em>), F is faraday constant (<em>96485 J/Vmol</em>) And E° is the standard cell potential

Replacing:

-550587J = - 2mol×96485J/Vmol×E⁰

<em>E° = 2,85V</em>

I hope it helps!

3 0
3 years ago
Tetrachloromethane,CC15,is classified as a
prohojiy [21]
Correct Answer: compound because the atoms of the elements are combined in a fixed proportion.
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4 years ago
Why do populations of bacteria in nature eventually stop growing
LekaFEV [45]
They run out of nutrients or supplies. such as other organisms
8 0
3 years ago
Read 2 more answers
What mass of solid sodium formate (of MW 68.01) must be added to 150 mL of 0.42 mol/L formic acid (HCOOH) to make a buffer solu-
Sergio [31]

Answer:

We need 4.28 grams of sodium formate

Explanation:

<u>Step 1:</u> Data given

MW of sodium formate = 68.01 g/mol

Volume of 0.42 mol/L formic acid = 150 mL = 0.150 L

pH = 3.74

Ka = 0.00018

<u>Step 2:</u> Calculate [base)

3.74 = -log(0.00018) + log [base]/[acid]

0 = log [base]/[acid]

0 = log [base] / 0.42

10^0 = 1 = [base]/0.42 M

[base] = 0.42 M

<u>Step 3:</u> Calculate moles of sodium formate:

Moles sodium formate = molarity * volume

Moles of sodium formate = 0.42 M * 0.150 L = 0.063 moles

<u>Step 4:</u> Calculate mass of sodium formate:

Mass sodium formate = moles sodium formate * Molar mass sodium formate

Mass sodium formate = 0.063 mol * 68.01 g/mol

Mass sodium formate = 4.28 grams

We need 4.28 grams of sodium formate

4 0
3 years ago
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