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jekas [21]
3 years ago
12

Using the chemical equation below, how many moles of Al2O3 produce when 105 grams of Al are reacted? 2Al+Fe2O3 —> Al2O3+2Fe

Chemistry
1 answer:
topjm [15]3 years ago
4 0

Answer:

1.94

Explanation:

moles = mass/Mr so you have 3.889 moles of aluminium, but because the ratio in the equation is 2:1 you need to halve it.

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Write a 4-line paragraph to explain what is melting.
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Answer:

Melting  is the process of being changed from a solid to a liquid state especially by the application of heat. This occurs when the energy of the solid increases, which increases the substance's temperature to the melting point.  Typically, the solids energy increases by the application of heat or pressure. At the melting point, the ordering of molecules in the solid breaks down to a less ordered state, and the solid "melts" to become a liquid.

hope this helps! :)

7 0
2 years ago
The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo
Snezhnost [94]

<u>Answer:</u> The solubility product of silver (I) phosphate is 9.57\times 10^{-10}

<u>Explanation:</u>

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)  

                            3s                  s

The expression of K_{sp} for above equation follows:

K_{sp}=(3s)^3\times s

We are given:  

s=2.44\times 10^{-3}M

Putting values in above expression, we get:

K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}

Hence, the solubility product of silver (I) phosphate is 9.57\times 10^{-10}

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Explanation:

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