Given that the triangle is dilated by factor 3, the image will be found as follows; The object is at: A(-7,-3), B(-3,-2), C(-4,-5) when the image was enlarged the new coordinates will be: A'=3(-7,-3)=(-21,-9) B'=3(-3,-2)=(-9,-6) C'=3(-4,-5)=(-12,-15) since the image is centered at the point (-7,-6), the final point will be at: A"=[(-21+-7),(-9+-6)=(-28,-15) B''=[(-9+-7),(-6+-6)]=(-16,-12) C''=[(-12+-7),(-15+-6)]=(-19,-17) thus the coordinates of the final image are: A''(-28,-15),B''(-16,-12),C''(-19,-17)
Well you subtract d from both sides with would make 2D-4=-8. Then you subtract four to both sides which is -12. Then you divide -12 by 2D which is 6. D=-6
well, this is just a matter of simple unit conversion, so let's recall that one revolution on a circle is just one-go-around, radians wise that'll be 2π, and we also know that 1 minute has 60 seconds, let's use those values for our product.
To round off a number to its nearest whole number, look at the first number after the decimal point. If the number is equal or greater than 5, add 1 to the number before the decimal point. If it is less than 5, add zero.
Because the first number after the decimal point is 3, which is less than 5, add zero to 16 . 16 + 0 = 16
If the number were 16.571, rounding off to the nearest whole number would give 17