Question

3 bananas are to be selected from a group of 9. In how many ways can this be done?

Answer 1

9C3 =9!/((9-3)!3!) =84 ways

Answer 2

Answer: 84

Step-by-step explanation:

The formula to calculate the number of ways to select x things from n things is given by :-

$^nC_x=\dfra{n!}{{!(n-x)!}$

Now, if 3 bananas are to be selected from a group of 9, then the number of ways  will be  

$^9C_3=\dfrac{9!}{3!(9-3)!}=\dfrac{9\times8\times7\times6!}{6\times6!}=84$

Hence, the  number of ways to select 3 bananas from a group of 9 =84