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iVinArrow [24]
2 years ago
9

Eq 1 X+Y=16 Eq 2 6x+9y=120 Solve by substitution Solve step by step

Mathematics
1 answer:
Alexxx [7]2 years ago
7 0

Answer:

X = 8, Y = 8

Step-by-step explanation:

Step 1) Solve for Y w/ bottom equation to yield - y = -2/3x + 40/3.

Step 2) substitute equation into x + y = 16 to get 1/3x + 40/3 = 16 multiply by 3 to clear the fractions and get x + 40 = 48 - subtract 40 by both sides to get x = 8.

Step 3) Plug x = 8 into the bottom equation to get 48 + 9y = 120, subtract 48 by both sides to get 9y = 72 and then divide by 9. The product is y = 8.

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Help it's due tomorrow!!!!
zepelin [54]
8a^2 + 3a^2

11a^2 

since both have a^2 you only have to add the coefficients 
5 0
3 years ago
E
Evgesh-ka [11]

Answer:

He bought 20 shirts

Step-by-step explanation:

shirts -- x

pants -- 3/4 of x

Therefore,

He bought --- 28(3/4 of x) pants and 40(x) shirts.

So, 28(3/4 of x) + 40(x) = 1220

=> 21x + 40x = 1220

=> 61x = 1220

=> x = 20

He bought 20 shirts and 15 pants.

Thenks and meak me brainliest :))

3 0
2 years ago
Find the equation of the line containing (3,-2) and (5,5).
Mars2501 [29]

Answer:

y = 3.5x - 12.5

Step-by-step explanation:

First, find the slope using rise over run (y2 - y1 / x2 - x1) with the 2 points:

(-2 - 5) / (3 - 5)

-7/-2

= 3.5

Then, plug the slope and a point into y = mx + b to solve for b:

y = mx + b

5 = 3.5(5) + b

5 = 17.5 + b

-12.5 = b

Plug the slope and the y intercept into the equation y = mx + b

y = 3.5x - 12.5 will be the equation

7 0
3 years ago
Read 2 more answers
Need help solving this for two points for a graph...3x+3=0​
coldgirl [10]

3x + 3 = 0 //Subtract -3 on both sides

3x = -3 //Divide 3 on both sides

x = -1

Here x = -1 and y is all the values where x = -1, so basically from negative infinity to infinity.

Make sure when writing the solution, y is any value and x stays the same.

Solution: (-1,0) and (-1,1)

//Hope this helps

7 0
3 years ago
32/20 fully reduced in prime numbers
Andreas93 [3]

Answer:

8/5

Step-by-step explanation:

EL NUMERADOR Y EL DENONINADOR SE DIVIDEN AL MISMO TIEMPO

ENTRE LOS NÚMEROS PRIMOS EN ORDEN HASTA QUE YA NO PUEDAN

DIVIDIRSE.

3 0
3 years ago
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