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UkoKoshka [18]
3 years ago
15

Helpppp pleaseeee helppppp

Mathematics
1 answer:
Brums [2.3K]3 years ago
6 0

Answer:

2x-1=x+7

-x     -x

2x-1=7

+1      +1

2x=7

/2    /2

x=3.5

Step-by-step explanation:

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A right triangle is shown below: the area of the triangle above will equal one half of a rectangle that is 5 units long and_ uni
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The area of the triangle above will equal one half of a rectangle that is 5 units long and 3 units wide.
The area of the triangle is 7.5 units and the area of the rectangle is 15 units
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3 years ago
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write an equation in point-slope form for the line through the given point with the given slope (10,-9);m=-2​
fgiga [73]

Answer:

The answer is

<h2>y + 9 =  - 2(x - 10)</h2>

Step-by-step explanation:

To find the equation of a line given a point and slope we use the formula

<h3>y - y1 = m(x - x1)</h3>

where

m is the slope

( x1 , y1) is the point

From the question

Slope / m = - 2

The point is ( 10, - 9)

Substitute the values into the above formula

That's the final answer is

<h3>y + 9 =  - 2(x - 10)</h3>

Hope this helps you

5 0
3 years ago
Jane has 3 bags of apples. Each bag has a different number
larisa [96]

Answer:

8 with a remainder of 4

step by step explanation:

6 0
3 years ago
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Hello I need help Finding the probability
Stolb23 [73]
Each petal of the region R is the intersection of two circles, both of diameter 10. Each petal in turn is twice the area of a circular segment bounded by a chord of length 5\sqrt2, which implies the segment is subtended by an angle of \dfrac\pi2. This means the area of the segment is

\text{area}_{\text{segment}}=\text{area}_{\text{sector}}-\text{area}_{\text{triangle}}
\text{area}_{\text{segment}}=\dfrac{25\pi}4-\dfrac{25}2

This means the area of one petal is \dfrac{25\pi}2-25, and the area of R is four times this, or 50\pi-100.

Meanwhile, the area of G is simply the area of the square minus the area of R, or 10^2-(50\pi-100)=200-50\pi.

So

\mathbb P(X=R)=\dfrac{50\pi-100}{100}=\dfrac\pi2-1
\mathbb P(X=G)=\dfrac{200-50\pi}{100}=2-\dfrac\pi2
\mathbb P((X=R)\land(X=G))=0 (provided these regions are indeed disjoint; it's hard to tell from the picture)
\mathbb P((X=R)\lor(X=G))=\mathbb P(X=R)+\mathbb P(X=G)=1

4 0
4 years ago
Leta has $45 in her account in May how much money does she have in her account in august
inessss [21]
I don’t know but ask google
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