CH4 + 2O2→CO2 + 2H2O
Explanation:
CH4 + O2→CO2 + H2O
First look at the C atoms. At first glance they are balanced with 1 C on each side.
Now look at the H atoms. They are not balanced. There are 4 H atoms on the left side and 2 H atoms on the right. Place a coefficient of 2 in front of the H2O. We now have 4 H atoms on both sides.
CH4 + O2→CO2 + 2H2O
Now look at the O atoms. They are not balanced. There are 2 O atoms on the left side and 4 on the right. Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides.
CH4 + 2O2→CO2 + 2H2O
The equation is now balanced. Each side has 1 C atom, 4 H atoms, and 4 O atoms.
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Below is the solution:
pOH = - log (5.75 × 10^−4) = 3.24
<span>pH = 14 - 3.24 = 10.76</span>
<u>Answer:</u> The molarity of solution is 1.08 M
<u>Explanation:</u>
We are given:
(m/m) of phenol = 1.40 %
This means that 1.40 g of phenol is present in 100 g of solution.
To calculate volume of solution, we use the equation:

Density of solution = 0.9956 g/mL
Mass of solution = 100 g
Putting values in above equation, we get:

To calculate the molarity of solution, we use the equation:

We are given:
Mass of solute (phenol) = 1.40 g
Molar mass of phenol = 94.11 g/mol
Volume of solution = 100.442 mL
Putting values in above equation, we get:

Hence, the molarity of solution is 0.15 M
HNO3 + Ca —-> H2O + N20 + Ca(NO3)2