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3 years ago

how many particles of the part that orbits the nucleus is on the shell closest to the center of the atom?

Chemistry

2 answers:

kolezko [41]3 years ago

8 0

There are 2 atoms orbiting it.

Rudik [331]3 years ago

4 0

There are two orbiting

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Please help me I need these answers

Cerrena [4.2K]

1 is true

2 is d 7

3 is

1 e

2 b

3 d

4 a

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8 0

3 years ago

An electron can be added to halogen atom to force a halide ion with

Lilit [14]

An electron can be added to halogen atom to force a halide ion with 8 valence electrons

An atom can be defined as the smallest part of an element which can take part in a chemical reaction.

However whenever, an electron is added to halogen atom to force a halide ion with 8 different valence electrons

So therefore; an electron can be added to halogen atom to force a halide ion with 8 valence electrons

Learn more about halogens:

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4 0

2 years ago

Which statement best describes the domain and range of f(x) = -(7)X and g(x) = 7X7 O f(x) and g(x) have the same domain and the

Ivan

Answer:

The graph of this equation is shown in Figure 1. As you can see this is a straight line with negative slope and does not intersect the y-axis. So the ...

Explanation:

4 0

3 years ago

To a 25.00 mL volumetric flask, a lab technician adds a 0.150 g sample of a weak monoprotic acid, HA , and dilutes to the mark w

Elis [28]

Answer: The number of moles of weak acid is $4.24\times 10^{-3}$ moles.

Explanation:

To calculate the moles of KOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}\text{Volume of solution (in L)}}$

We are given:

Volume of solution = 43.81 mL = 0.04381 L (Conversion factor: 1L = 1000 mL)

Molarity of the solution = 0.0969 moles/ L

Putting values in above equation, we get:

$0.0969mol/L=\frac{\text{Moles of KOH}}{0.04381}\\\\\text{Moles of KOH}=4.24\times 10^{-3}mol$

The chemical reaction of weak monoprotic acid and KOH follows the equation:

$HA+KOH\rightarrow KA+H_2O$

By Stoichiometry of the reaction:

1 mole of KOH reacts with 1 mole of weak monoprotic acid.

So, $4.24\times 10^{-3}mol$ of KOH will react with = $\frac{1}{1}\times 4.24\times 10^{-3}=4.24\times 10^{-3}mol$ of weak monoprotic acid.

Hence, the number of moles of weak acid is $4.24\times 10^{-3}$ moles.

6 0

3 years ago

Oxyacids contains at least one h+ and an oxyanion. the " sulfurous " oxyacid contains the oxyanion ________.

Ulleksa [173]

The correct answer is Oxyanion Nitrite. Oxyanion is referred to as an ion which contains one or more oxygen atoms that are bonded to another chemical element. It has a generic formula of A. xO z− y, wherein A, stands for a chemical element, while O, stands for an Oxygen atom

7 0

3 years ago