Question

Use the equation to answer the question

Answer 1

If you change the 2 in front of 2O, to a 3, the result of the right side of the equation is $3CO_2+6H_2O$

Given the chemical equation expressed as:

$CH_4 + 2O_2 \rightarrow CO_2 + 2H_2O$

From the equation, we can see that 1 mole of methane reacts with 2 moles of oxygen to form 1 mole of carbon dioxide and 2 moles of water.

If the number of moles of oxygen is replaced with 3 moles, the correct equation will be expressed as:

$3CH_4 + 2(3O_2) \rightarrow3CO2 + 6H2O$

This shows that if you change the 2 in front of 2O, to a 3, the result of the right side of the equation is $3CO_2+6H_2O$

Learn more here: brainly.com/question/11904811

Answer 2

CH4 + 2O2→CO2 + 2H2O

Explanation:

CH4 + O2→CO2 + H2O

First look at the C atoms. At first glance they are balanced with 1 C on each side.

Now look at the H atoms. They are not balanced. There are 4 H atoms on the left side and 2 H atoms on the right. Place a coefficient of 2 in front of the H2O. We now have 4 H atoms on both sides.

CH4 + O2→CO2 + 2H2O

Now look at the O atoms. They are not balanced. There are 2 O atoms on the left side and 4 on the right. Place a coefficient of 2 in front of the O2. We now have 4 O atoms on both sides.

CH4 + 2O2→CO2 + 2H2O

The equation is now balanced. Each side has 1 C atom, 4 H atoms, and 4 O atoms.