Answer : The equilibrium concentration of
in the solution is, 
Explanation :
The dissociation of acid reaction is:

Initial conc. c 0 0
At eqm. c-x x x
Given:
c = 

The expression of dissociation constant of acid is:
![K_a=\frac{[H_3O^+][C_6H_5COO^-]}{[C_6H_5COOH]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BH_3O%5E%2B%5D%5BC_6H_5COO%5E-%5D%7D%7B%5BC_6H_5COOH%5D%7D)

Now put all the given values in this expression, we get:
![6.3\times 10^{-5}=\frac{(x)\times (x)}{[(7.0\times 10^{-2})-x]}](https://tex.z-dn.net/?f=6.3%5Ctimes%2010%5E%7B-5%7D%3D%5Cfrac%7B%28x%29%5Ctimes%20%28x%29%7D%7B%5B%287.0%5Ctimes%2010%5E%7B-2%7D%29-x%5D%7D)

Thus, the equilibrium concentration of
in the solution is, 
Answer:

Explanation:
Hello!
In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

Whereas solving for the final temperature T2, we get:

Thus, we plug in the given data (temperature in Kelvins) to obtain:

Best regards!
In stars helium atoms are used with hydrogen atoms in order to produce energy.
Answer: A )
Answer:
The answer to your question is: letter B.
Explanation:
Carbon atom double-bonded to an oxygen atom C= O,
a) Carbohydrate group this group does not exist
b)Carbonyl group This option is right, carbonyl group is C=O
c) Hydroxyl group This option is incorrect, hydroxyl group is OH, very different from C=O
d) Ketone group Ketone group does not exist, ketones have the same functional group as aldehydes (C=O)