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Mrac [35]
3 years ago
5

Given that

Mathematics
1 answer:
timofeeve [1]3 years ago
6 0

Answer:

4.

Step-by-step explanation:

(sec α - tan α)(sec α + tan α) = sec^2 α - tan^2α

But sec^2  α = 1 + tan^2 α so

sec^2 α - tan^2α  = 1 + tan^2 α - tan^2α

= 1

so 1 =  (sec α - tan α)(sec α + tan α) = 1/4 * x     where x  is sec α + tan α

1/4 * x = 1

x = 4.

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Answer:

After 3 weeks they both will have the same amount in their savings account.

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Amount saved by Haley = $155

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Amount spending each week by Hank = $15

We need to find Number of weeks when both both will have same amount in savings account.

Solution:

Let Number of week be 'x'.

Total Amount of Haley can be calculated by Amount saved by Haley plus Amount saving each week by Haley multiplied by number of weeks.

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Total Amount of Haley = 155+10x

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Now we need to find the number of weeks when both will have same amount.

To find the same we will have to make both the equation equal.

So we can say.

155+10x=230-15x

On Solving above equation we get;

We will combine the like terms together;

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Now Dividing both side by 25 using Division property of equality we get;

\frac{25x}{25} = \frac{75}{25}\\\\x=3 \ weeks

Hence, After 3 weeks they both will have the same amount in their savings account.

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