Answer: Gail could have from 0 to 8.5 and Jim could have 10 to 18.5
Step-by-step explanation:
Gail = G
Jim = G + 10
J + G <= 27 ∴
G+10+G <=27
2G + 10 <= 27
2G <= 27 - 10
2G <= 17
G <= 17/2
G <= 8.5
As it is money, let's not say that they have negative money.
So, Gail has from 0 to 8.5. As Jim has 10 more than Gail, he has from 10 to 18.5. At the most : 8.5 + 18.5 = 27.
<em>commutative property</em> a + b = b + a
... (-5 + 1/2 + 5) = ... (-5 + 5 + 1/2)
<em>inverse property of addition</em> a + (-a) = a - a = 0
... (-5 + 5 + 1/2) = ... (0 + 1/2)
<em>identity property of addition</em> a + 0 = 0 + a = a
... (0 + 1/2) = ... 1/2
<em>inverse property of multiplication</em> a/b · b/a = 1
37 · 2 · 1/2 = 37 · 2/1 · 1/2 = 37 · 1
<em>identity property of multiplication</em> a · 1 = 1 · a = a
37 · 1 = 37
Answer:
Step-by-step explanation:
In the past, mean of age of employees
i.e.
Recently sample was taken
n = sample size = 60
Mean of sample = 45
Std dev of sample s = 16
(Right tailed test)
Since only population std deviation is known we can use t test only
Std error =
Mean difference = 45-40 =5
Test statistic t=
df = 60
p value =0.008739
Since p < 0.05 we reject null hypothesis
The mean age has increased.