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Feliz [49]
3 years ago
6

Jim has ten more dollars than Gail. Together they have at most twenty-seven dollars. A. Determine the possible amounts of money

Gail could have. B. Sketch the solution on a number line.

Mathematics
2 answers:
Irina18 [472]3 years ago
4 0
Gail could have up to 17 dollars. 
Len [333]3 years ago
3 0

Answer: Gail could have from 0 to 8.5 and Jim could have 10 to 18.5

Step-by-step explanation:

Gail = G

Jim = G + 10

J + G <= 27 ∴

G+10+G <=27

2G + 10 <= 27

2G <= 27 - 10

2G <= 17

G <= 17/2

G <= 8.5

As it is money, let's not say that they have negative money.

So, Gail has from 0 to 8.5. As Jim has 10 more than Gail, he has from 10 to 18.5. At the most : 8.5 + 18.5 = 27.

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Varvara68 [4.7K]

Answer: <u>2x+y=-8</u> = <u>x=-1/2y-4  </u>        

<u>4x-6y=-24 </u>= <u>x =3/2y-6</u>

Step-by-step explanation:

2x+y=-8 -- Step 1: Add -y to both sides.

2x+y+−y=−8+−y

2x=−y−8

Step 2: Divide both sides by 2.

2x/2=-y-8/2

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4x-6y=-24 -- Step 1: Add 6y to both sides.

4x−6y+6y=−24+6y

4x=6y−24

Step 2: Divide both sides by 4.

4x/4=6y-24/4

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3 years ago
How do I solve this problem?
lara31 [8.8K]

Answer:

x = 12

Step-by-step explanation:

(whole secant) x (external part) =  (whole secant) x (external part)

(6+x) *6 = (4+23) * 4

(6+x) *6 = 27*4

6(6+x) = 108

Divide each side by 6

6+x =18

Subtract 6 from each side

6+x-6 =18-6

x = 12

8 0
4 years ago
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PLEASE HELP ASAP!!!!!! WILL GIVE BRAINLEST TO FIRST CORRECT ANSWER!!!!!
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Answer:

THE ANSWER IS THE 1ST,2ND, AND 4TH.

Step-by-step explanation:

i just did this question and this is the answer it gave me! hope this helped!!! have a good day babes!

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3 years ago
Please answer this question! 15 points and brainliest!
Dmitry [639]

ANSWER: x = 0.6


Step-by-step explanation'

Step 1.

add 1 to each side to get rid of the 1

Step 2.)

Now, your equation is 6x = 10

Step 3.)

Divide each side by 6 to completely isolate the variable x

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3 years ago
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What is the following product?
Zarrin [17]

Answer: A

Step-by-step explanation:

(\sqrt{12}+\sqrt{6})(\sqrt{6}-\sqrt{10})

(\sqrt{12}*\sqrt{6})-(\sqrt{12}* \sqrt{10})+(\sqrt{6}*\sqrt{6})-(\sqrt{6}*\sqrt{10})

(\sqrt{12*6})-(\sqrt{12*10})+(\sqrt{6*6})-(\sqrt{6*10})

Let's rewrite the numbers inside to see if we can take some out.

For example; 12 is 3 x 4 and 4 is 2^2 which means a 2 will come out of the root.

(\sqrt{3*2^2*6})-(\sqrt{3*2^2*10})+(\sqrt{6^2})-(\sqrt{6*10})

(2\sqrt{18})-(2\sqrt{30})+(6)-(\sqrt{60})

We can also rewrite 18 as 9 x 2 and 9 can be rewritten as 3^2 which will make the 3 come out.

60 can be rewritten as 15 x 4 and 4 can be rewritten as 2^2 which will make the 2 come out.

Let's rewrite this.

(2\sqrt{2*3^2})-(2\sqrt{30})+(6)-(\sqrt{15*2^2})

When a number comes out of a root, it has to be multiplied by the number that is already outside.

(2*3\sqrt{2})-(2\sqrt{30})+(6)-(2\sqrt{15})

Solve and eliminate parentheses.

6\sqrt{2}-2\sqrt{30}+6-2\sqrt{15}

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3 years ago
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