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3 years ago

HELP does anyone get these three questions?

Mathematics

1 answer:

Tom [10]3 years ago

8 0

Step-by-step explanation:

since we have the relation (inches/dollars)

4.3 inches down per dollar

per 10 dollars 43 inches down

per half a dollar 2.15 inches down

per 63.60 dollars 273.48 inches down

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What is reciprocal of the number 5

Hatshy [7]

Answer:

1/5

Step-by-step explanation:

5 = 1/5

6= 1/6

1/6= 6/1 (or just 6)

5/6= 6/5

Do you see the pattern?

Every number has a reciprocal except for 0. There is nothing you can multiply by 0 to create a product of 1, so it has no reciprocal.

8 0

3 years ago

Read 2 more answers

IF THERE IS A TEACHER out there please answer 6=4x+9y

miskamm [114]

Answer:

$y=-\frac{4}{9}x +\frac{2}{3}$

Step-by-step explanation:

I'm going to presume you want this linear equation in slope-intercept form, so start with:

$6=4x+9y$

Subtract $9y$ from both sides of the equation:

$-9y+6=4x$

Subtract $6$ from both sides of the equation:

$-9y=4x-6$

Divide both sides of the equation by the coefficient of $y$ , which is $-9$ :

$y=\frac{4}{-9}x +\frac{-6}{-9}$

Simplify:

$y=-\frac{4}{9}x +\frac{2}{3}$

5 0

3 years ago

Read 2 more answers

I will give brainliest to first (2x^2 − 7x^3 + 8x) + (−8x^3 − 3x^2 + 4)

cluponka [151]

Answer:-15x^3-x^2+8x+4

Sry if I am wrong

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Help pleaseeee! ASAP

34kurt

Answer:

Step-by-step explanation:

5 0

3 years ago

Help!! Answer !!! about to run out of time in test!!

Gemiola [76]

$\qquad \qquad\huge \underline{\boxed{\sf Answer}}$

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

$\qquad \sf \dashrightarrow \: h {}^{2} = {8}^{2} + {6}^{2}$

$\qquad \sf \dashrightarrow \: h {}^{2} = {36}^{} + {64}^{}$

$\qquad \sf \dashrightarrow \: h {}^{2} = 100$

$\qquad \sf \dashrightarrow \: h {}^{} = \sqrt{100}$

$\qquad \sf \dashrightarrow \: h {}^{} = {10}$

Now, let's find the asked values ~

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{opposite \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \sin(x) = \dfrac{3}{5} \: or \: 0.6 \: units$

For Cos y :

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{adjcant \: side}{hypotenuse}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{6}{10}$

$\qquad \sf \dashrightarrow \: \cos(y) = \dfrac{3}{5} \: or \: 0.6 \: units$

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0

2 years ago