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3 years ago

Solve x 2 + 9x + 8 = 0 by completing the square. What are the solutions?

Mathematics

1 answer:

vivado [14]3 years ago

3 0

x^2+9x+8=0

(x+1)(x+8)=0

x+1=0

x=-1

x+8 = 0

x=-8

solutions are -1 and -8

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mark ordere wome balloons for a party that she is having.The balloons cost $4.50 each and there is a service fee of $12.The tota

ohaa [14]

A general equation to use for this situation is y = mx + b.

For this question, we can assume that y is total cost, m is cost per balloon, x is the amount of balloons, and b as the service fee; so we can set the equation up:

y = (4.50)x + 12

And we can further plug in the total cost to find the number of balloons purchased for the party:

79.50 = (4.50)x + 12

Now we can solve for x (number of balloons):

67.50 = (4.50)x

x = 15

The total number of balloons purchased for the party is 15.

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2 years ago

Charles owes $2,500 on a credit card. The card charges 12% interest compounded continuously. Write a formula that describes how

ella [17]

Answer:

see below

Step-by-step explanation:

The formula for the amount resulting from P earning interest at rate r continuously compounded is ...

A = Pe^(rt)

for P=2500 and r=0.12, this becomes ...

A = 2500e^(0.12t)

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3 years ago

Give a girl gave me head would I get any disease

stiks02 [169]

Answer:

No, but you could give her a disease. You should get tested before any type of sexual interaction

Step-by-step explanation:

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2 years ago

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3 years ago

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Researchers measured the data speeds for a particular smartphone carrier at 50 airports. The highest speed measured was 75.6 Mbp

olga55 [171]

Answer:

a) 59.98

b) 2.99

c) 2.99

d) Significantly High

Step-by-step explanation:

Part a)

Highest speed measured = x = 75.6 Mbps

Average/Mean speed = $\overline{x}$ = 15.62 Mbps

Standard Deviation = s = 20.03 Mbps

We need to find the difference between carrier's highest data speed and the mean of all 50 data speeds i.e. x - $\overline{x}$

x - $\overline{x}$ = 75.6 - 15.62 = 59.98 Mbps

Thus, the difference between carrier's highest data speed and the mean of all 50 data speeds is 59.98 Mbps

Part b)

In order to find how many standard deviations away is the difference found in previous part, we divide the difference by the value of standard deviation i.e.

$\frac{59.98}{20.03}=2.99$

This means, the difference is 2.99 standard deviations or in other words we can say, the Carrier's highest data speed is 2.99 standard deviations above the mean data speed.

Part c)

A z score tells us that how many standard deviations away is a value from the mean. We calculated the same in the previous part. Performing the same calculation in one step:

The formula for the z score is:

$z=\frac{x-\overline{x}}{s}$

Using the given values, we get:

$z=\frac{75.6-15.62}{20.03}=2.99$

Thus, the Carriers highest data is equivalent to a z score of 2.99

Part d)

The range of z scores which are neither significantly low nor significantly high is -2 to + 2. The z scores outside this range will be significant.

Since, the z score for carrier's highest data speed is 2.99 which is well outside the given range, i.e. greater than 2, we can conclude that the carrier's highest data speed is significantly higher.

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3 years ago