Answer:
26
Step-by-step explanation:
One person can pack 45 cartoons per hour
Therefore the number of people needed to pack 1200 cartons can be calculated as follows
= 1200/45
= 26.66
= hence 26 people are needed to pack 1200 cartoons
Rather than carrying out IBP several times, let's establish a more general result. Let

One round of IBP, setting


gives


This is called a power-reduction formula. We could try solving for
explicitly, but no need.
is small enough to just expand
as much as we need to.





Finally,

so we end up with


and the antiderivative is

=ligma baalls so that I can tape this d to your fore head so you can cd’s nuts
Step-by-step explanation:
4y
4 (5)
4×5
20
y=20
Hope its helpfulllll
Answer:
<h2>
-4</h2>
Option B is the correct option.
Step-by-step explanation:

Subtract the numbers

Multiply the numbers

Evaluate the power

Calculate the difference

Hope this helps..
Best regards!!