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3 years ago

9

Is the equation y = x3 even, odd, or neither?

2 answers:

m_a_m_a [10]3 years ago

8 0

It's probably gonna be neither

Zinaida [17]3 years ago

7 0

For an odd function, f(-x)=-f(x)
for an even function, f(-x)=f(x)
to determine which, just try out a few numbers or look at a graph
I believe its neither

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Answer this and show steps question #1,3,4

zimovet [89]

Here you go. Just remember PEMDAS. P-parentheses E- exponents M-multiplication D-division A-addition S-subtraction That is the order you will do it in.

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4 years ago

A club charges $40 for membership fee and $3/hour for using it. If he used the club for 60 hours what is the total cost.

Arlecino [84]

Total cost is 220 dollars. This is because 3 times 60 is 180 and plus membership fee of 40 dollars is 220 dollars.

7 0

3 years ago

Read 2 more answers

A 228<br> B 328<br> C 488<br> D 572

Aleksandr [31]

Answer:

G 328 ft

Step-by-step explanation:

$\cos(angleBAC) = \frac{AB}{AC}$

$\cos(55°) = \frac{AB}{400}$

AB = 229.431 ft

AB² + BC² = AC²

229.431² + h² = 400²

h = 327.659 ft ≈ 328 ft

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2 years ago

A large stand of fir trees occupies 24 hectares. The trees have an average density of 1 tree per 20m squared. A forester estimat

Leona [35]

Answer:

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

Step-by-step explanation:

First, let is find the total amount of fir trees that occupies the area of 24 hectares. (1 hectare = 10000 square meters)

$n = \sigma \cdot A$

Where:

$\sigma$ - Surface density, measured in trees per square meter.

$A$ - Total area, measured in square meters.

Given that $\sigma = \frac{1}{20}\,\frac{tree}{m^{2}}$ and $A = 24\,h$ , the total amount of fir trees is:

$n = \left(\frac{1}{20}\,\frac{trees}{m^{2}} \right)\cdot (24\,h)\cdot \left(10000\,\frac{m^{2}}{h} \right)$

$n = 12000\,trees$

It is known that one-tenth of the tress are cut, whose amount is:

$n_{c} = 0.1 \cdot n$

$n_{c} = 0.1 \cdot (12000\,trees)$

$n_{c} = 1200\,trees$

If each tree will yield 300 board-feet, then the yield related to the trees that are cut is:

$y = S\cdot n_{c}$

Where:

$S$ - Yield of the tress, measured in board-feet per tree.

$n_{c}$ - Amount of trees that will be cut, measured in trees.

If $n_{c} = 1200\,trees$ and $S = 300\,\frac{b-ft}{tree}$ , then:

$y = \left(300\,\frac{b-ft}{tree} \right)\cdot (1200\,trees)$

$y = 360000\,b-ft$

The yield of the stand if one-tenth of the trees are cut is 360000 board-feet.

8 0

3 years ago

Rachel and Hugo sorted 236 crayons into boxes for a local arts project. Each box had 10 crayons. How many crayons were left over

Kryger [21]

This is a simple division problem. Since there are 236 crayons, in groups of ten, there will be 6 left over because there is a 6 in the ones place.

8 0

3 years ago

Read 2 more answers