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3 years ago

Y’all. I need you to help me

Mathematics

1 answer:

Sergio039 [100]3 years ago

3 0

Answer:

Step-by-step explanation:

PQ/QR = ST/TR

17.5/QR = 7/4

QR = (17.5 x 4)/7

QR = 70/7

QR = 10

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The grades on a math midterm at Springer are roughly symmetric with \mu = 78μ=78mu, equals, 78 and \sigma = 5.0σ=5.0sigma, equal

mr Goodwill [35]

Answer:

-2.8

Step-by-step explanation:

Given that:

Mean, μ = 78

Standard deviation, σ = 5

Omar's score, x = 64

The Zscore of Omar's score :

Zscore = (x - μ) ÷ σ

Zscore = (64 - 78) / 5

Zscore = - 14 / 5

Zscore = - 2.8

Hence, Omar's exam score is - 2.8

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3 years ago

What’s an injective function?

Tanya [424]

Answer:

an Injective function is a function that maps distinct elements of its domain to distinct elements of its codomain. In other words, every element of the function's codomain is the image of at most one element of its domain.

Step-by-step explanation:

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3 years ago

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A school has 600 students. If 5% are absent, how many students are absent?

qwelly [4]

Answer:

30 students are absent.

Step-by-step explanation:

5%=0.05

0.05*600=30

8 0

3 years ago

Read 2 more answers

The price of a sweater is $5 less than twice the price of a shirt. if four sweaters and three shirts cost $200, find the price o

Mandarinka [93]

Sw+5=2sh
4sw+3sh=200 
4(2sh-5)+3sh=200

$20, $35 The shirts are $20 and the sweaters are $35

8 0

3 years ago

Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the p

PIT_PIT [208]

Answer:

Colin has 8 sheets left for his third class.

Step-by-step explanation:

Given that:

Total Number of pieces of papers = $x$

Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad

Writing the equation:

$\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)$

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

$\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)$

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

$\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8$

So, the answer is:

Colin has 8 sheets left for his third class.

5 0

3 years ago