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crimeas [40]
3 years ago
14

7.3 is what percent of 139?

Mathematics
1 answer:
Kobotan [32]3 years ago
5 0
7.3 x 100 / 139 = 5.25%

answer
<span>7.3 is 5.25% of 139</span>
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2. After the relay race, Larry, Curly, and Moe went to the
jarptica [38.1K]

Using proportions, it is found that each of the 6 people got $0.5.

<h3>Proportions:</h3>
  • This question is solved by <em>proportions</em>, using a rule of three.
  • $3.00 is shared between 6 people, which are Larry, Curly, Moe, Alvin, Simon and Theodore. How much did each people(1 person) get?

The <em>rule of three</em> is:

$3.00 - 6 people

$x - 1 person

Applying cross multiplication:

6x = 3

x = \frac{3}{6}

x = 0.5

Each of the 6 people got $0.5.

To learn more about proportions, you can take a look at brainly.com/question/24372153

7 0
2 years ago
Regina left the coffee shop traveling 9 mph. Then, 3 hours later, Janai left traveling the same direction at
damaskus [11]

Answer:

<em>suwi6q74diyer7ityw7reuDjuss36audlsgo74wridoyaurslhjsgjfaufalakateUd</em>

Step-by-step explanation:

will3urafg-"7'-"/-()4<u> </u><u>mhl374</u><u>y</u><u>3</u><u>l</u><u>u</u><u>s</u><u>d</u><u>u</u><u>s</u><u>i</u><u>t</u><u>z</u><u>l</u><u>a</u><u>7</u><u>w</u><u>h</u><u>f</u><u>z</u><u>s</u><u>p</u><u>r</u><u>X</u><u>j</u><u>a</u><u>u</u><u>e</u><u>g</u><u>k</u><u>z</u><u>h</u><u>r</u><u>o</u><u>y</u>

5 0
2 years ago
Write the number 5 million 4 thousand three hindered in standard form
Sphinxa [80]

Answer:

The ans is 5004300

In standard form,

5004300. Five Millon four thousand and three hundred.

(hope that helped can i plz have brainlist it wil make my day :D hehe)

Step-by-step explanation:

7 0
3 years ago
A student union cafeteria worker checked the weight of ten half-pound bags of whole bean coffee and recorded the following weigh
Likurg_2 [28]

Answer: σ = 0.0154

Step-by-step explanation:

1. Calculate the mean for the recorded data.

(0.48 + 0.51 + 0.47 + 0.49 + 0.49 + 0.50 + 0.52 + 0.48 + 0.49 + 0.51)/10 =

4.94 / 10 = 0.49

The mean is represented with the greek letter μ, so μ = 0.49

2. For each element in the serie, subtract the mean (0.49) and square the result

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

(0.47 - 0.49)^2 = (-0.02)^2 = 0.0004

(0.49 - 0.49)^2 = 0

(0.49 - 0.49)^2 = 0

(0.50 - 0.49)^2 = (0.01)^2 = 0.0001

(0.52 - 0.49)^2 = (0.03)^2 = 0.0009

(0.48 - 0.49)^2 = (-0.01)^2 = 0.0001

(0.49 - 0.49)^2 = 0

(0.51 - 0.49)^2 = (0.02)^2 = 0.0004

So we get these results: 0.0001, 0.0004, 0.0004, 0, 0, 0.0001, 0.0009, 0.0001, 0, 0.0004

3. Now, we calculate the mean of these squared differences

(0.0001 + 0.0004 + 0.0004 + 0 + 0 + 0.0001 + 0.0009 + 0.0001 + 0 + 0.0004) / 10 =

(0.0024) / 10 = 0.00024

4. Now to get the standard deviation, we need to get the root of this last value (0.00024).

√(0.00024) = 0.0154

5. So that will be our standard deviation value:

σ = 0.0154

DONE!

7 0
3 years ago
What set of reflections would carry trapezoid ABCD onto itself? (1 point) Trapezoid ABCD is shown. A is at negative 5, 1. B is a
amid [387]

Answer:

y=x, x axis,  y=x, y axis

Step-by-step explanation:

If a point A(x, y) is reflected along the y = x line, the new coordinates would be A'(y, x)

If a point A(x, y) is reflected across the x axis, the new coordinates would be A'(x, -y)

If a point A(x, y) is reflected along the y axis, the new coordinates would be A'(-x, y)

Firstly reflect Trapezoid ABCD along the y = x line to give:

A (-5, 1) ⇒ A'(1, -5). B (-4, 3) ⇒ B'(3, -4). C (-2, 3) ⇒C'(3, -2). D (-1, 1) ⇒ D'(1, -1)

Secondly reflect along the x axis to give:

A'(1, -5)⇒ A"(1,5). B'(3, -4)⇒ B"(3,4), C'(3, -2)⇒C"(3, 2), D'(1, -1) ⇒ D"(1, 1)

Thirdly reflect along the y = x line to give:

A"(1,5) ⇒ A"'(5, 1). B"(3,4) ⇒ B"'(4, 3). C"(3, 2) ⇒ C"'(2, 3). D"(1, 1) ⇒ D"'(1, 1)

Lastly reflect along the y axis to give:

A"'(5, 1) ⇒ A""(-5, 1), B"'(4, 3) ⇒ B""(-4, 3), C"'(2, 3) ⇒ C""(-2, 3), D"'(1, 1) ⇒ D""(-1.1)

6 0
4 years ago
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