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fredd [130]
3 years ago
13

What is the slope of OA?

Mathematics
1 answer:
schepotkina [342]3 years ago
7 0

Answer:

D) b/a

From the given figure, O = (0, 0) and A = (a, b)

Slope of OA = (y2 - y1) / (x2 - x1)

Here x1 = 0, y1 = 0, x2 = a and y2 = b.

Slope of OA = (b - 0)/(a - 0)

Slope of OA = b/a

Answer: D) b/a

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Answer:

B) measures of variability

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7 0
3 years ago
Find the perimeter
MAXImum [283]

Answer:

  5 + 8 + 11 + 10 = 34

Step-by-step explanation:

The lengths of the horizontal and vertical sides are easily determined. The slant side is seen to be the hypotenuse of a 3-4-5 triangle (times 2), so is 10 units long. The perimeter is the sum of the side lengths:

  5 + 8 + 11 + 10 = 34

_____

You can always estimate the length of the hypotenuse of a right triangle as being between 1 and 1.5 times the length of the <em>longest</em> side. Here, the longest side of the right triangle whose hypotenuse is of interest is 8 units, so the hypotenuse will be between 8 and 12 units long. That means the perimeter of the blue trapezoid will be between 32 and 36, a guess of sufficient accuracy to allow you to choose the correct answer.

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5 0
3 years ago
Indicate True of False for 3g &gt; 15 Substitute 5 for g.
olga55 [171]

Answer:

False

Step-by-step explanation:

(3)(5)>15

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7 0
3 years ago
A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are
Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764

There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

(b) What is the probability that all three of the bulbs have the same rating?

P = P_{1} + P_{2} + P_{3}

P_{1} is the probability that all three of them are 13-watt. So:

P_{1} = \frac{8}{24}*\frac{7}{23}*\frac{6}{22} = 0.0277

P_{2} is the probability that all three of them are 18-watt. So:

P_{2} = \frac{9}{24}*\frac{8}{23}*\frac{7}{22} = 0.0415

P_{3} is the probability that all three of them are 23-watt. So:

P_{3} = \frac{7}{24}*\frac{6}{23}*\frac{5}{22} = 0.0173

P = P_{1} + P_{2} + P_{3} = 0.0277 + 0.0415 + 0.0173 = 0.0865

There is a 8.65% probability that all three of the bulbs have the same rating.

(c) What is the probability that one bulb of each type is selected?

We have to permutate, permutation of 3(bulbs), with (1,1,1) repetitions(one for each type). So

P = p^{3}_{1,1,1}*\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 3**\frac{8}{24}*\frac{9}{23}*\frac{7}{22} = 0.1245

There is a 12.45% probability that one bulb of each type is selected.

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3 years ago
What is the missing term in the factorization of 2x2 + 5x + 3?<br><br> (2x + 3)(x + )
nata0808 [166]
(x + 1)

As:

(2x + 3)(x + 1) = 2x2 + 2x + 3x + 3

= 2x2 + 5x + 3
3 0
3 years ago
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