Answer:
it is half the area of a square of side length 8
Step-by-step explanation:
area of a square = l × b
= 8 × 8
= 64 cm^2
area of a triangle = b × h ÷ 2
= 8 × 8 ÷ 2
= 64 ÷ 2
= 32 cm^2
hope you can understand ☆☆☆
Slope (y2-y1)/(x2-x1)
(10-0)/(10-8) = 10/2 = 5
The slope is 5
y=mx+b
first find the y intercept or b or x=0
b=5
now find the slope
y²-y¹/x²-x¹--> 5-2/0-(-2)
m=3/2
the equation is D. y=3/2x+5
Looking at the problem statement, this question states for us to determine the range of the function that is provided in a graph is. Let us first determine what range is.
- Range ⇒ Range is what y-values can be used in the function that is graphed. For example, if a line just goes up and down all the way to negative and positive infinity, then the range would be negative infinity to positive infinity as it includes all of the y-values in it's solutions.
Now moving back to our problem, we can see that we have a vertex at (2, -5) and that the lowest y-values is at y = -5. Therefore the y-values would be anything greater than or equal to -5 and less than infinity because the lines go forever up in the positive-y-direction.
Therefore, the option that would best match the description that we provided would be option B, -5 ≤ y < ∞.
