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NemiM [27]
2 years ago
14

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.

0 minutes. Find the probability that a given class period runs between 51.5 and 51.75 minutes.
Find the probability of selecting a class that runs between 51.5 and 51.75 minutes.
Mathematics
1 answer:
yuradex [85]2 years ago
3 0
Given:

Uniform distribution of length of classes between 45.0 to 55.0 minutes. 

To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:

45+55/2 = 50

So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
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irina1246 [14]

Answer:

30 students

Step-by-step explanation:

80%  of  N   =   24            where N  is  the total number of students

So

.80 N   =  24

N =  24 /  .80     =      30

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Expand log_1/2(3x^2/2) using the properties and rules for logarithms.<br><br><br> Please help.
Naily [24]

Answer:

\frac{0.1761+2\log(x)}{-0.3010}

Step-by-step explanation:

Data provided:

\log_{1/2}(\frac{3x^2}{2})

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) \log(\frac{A}{B}) = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3x^2) - \log_{1/2}(2)

or

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+\log_{\frac{1}{2}}(x^2) - \log_{1/2}(2)

or

using property 3

\log_{1/2}(\frac{3x^2}{2}) = \log_{1/2}(3)+2\log_{\frac{1}{2}}(x) - \log_{1/2}(2)

also,

\log_a(x)=\frac{\log(x)}{\log(a)}

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.4771+2\log(x)-0.3010}{0-0.3010}

or

\log_{1/2}(\frac{3x^2}{2}) = \frac{0.1761+2\log(x)}{-0.3010}

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3 years ago
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△ABC is mapped to △A′B′C′ using each of the given rules.
Norma-Jean [14]

Answer:

(x,y)→(x+5,y) will be congruent; (x,y)→(5x,5y) will not be congruent; (x,y)→(0.5x, 0.5y) will not be congruent; (x,y)→(x,-y) will be congruent; (x,y)→(-x,-y) will be congruent.

Step-by-step explanation:

The types of translations that result in congruent images are translations or slides; reflections; and rotations.  

Translations will add to the x- and y-coordinates; this is why the first transformation is congruent.

Reflections will negate one or more of the coordinates; this is why the fourth and fifth transformations are congruent.

The remaining two are dilations; these are stretches or shrinks that occur when the coordinates are multiplied by a number other than 1.  These change the size of the figure, which is why they are not congruent.

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2 years ago
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