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NemiM [27]
2 years ago
14

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.

0 minutes. Find the probability that a given class period runs between 51.5 and 51.75 minutes.
Find the probability of selecting a class that runs between 51.5 and 51.75 minutes.
Mathematics
1 answer:
yuradex [85]2 years ago
3 0
Given:

Uniform distribution of length of classes between 45.0 to 55.0 minutes. 

To determine the probability of selecting a class that runs between 51.5 to 51.75 minutes, find the median of the given upper and lower limit first:

45+55/2 = 50

So the highest number of instances is 50-minute class. If the probability of 50 is 0.5, then the probability of length of class between 51.5 to 51.75 minutes is near 0.5, approximately 0.45. <span />
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Type the correct answer in each box. use numerals instead of words. the number of customers who come into julie's antique shop o
vladimir1956 [14]
She will also need the minimum value, the median, the upper quartile and the lower quartile.

The box will be drawn from the upper quartile to the lower quartile, with a vertical line at the median.  The whiskers will go from the box to the highest and lowest values.
3 0
2 years ago
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Help! This is due today and I'm stuck on this problem.
Varvara68 [4.7K]

Answer:

280.6 m^2

Step-by-step explanation:

<u>find the length of each side:</u>

you're only given h = 9 m

the formula for h is  h=\frac{\sqrt{3} }{2} *a, where a is a side length of the hexagon

plug h in:

9=\frac{\sqrt{3}}{2}*a\\\\a=9*\frac{2}{\sqrt{3}}\\\\

a ≈ 10.392 m

<u>now find the area of a triangle:</u>

1/2 (10.392)(9) = 46.764 m^2

multiply that by 6 and you get 280.584 ≈ 280.6 m^2

you can also use the regular hexagon area formula instead of finding the individual area and multiplying by 6: \frac{3\sqrt{3} }{2} *a^2

7 0
2 years ago
Read 2 more answers
Meg lives in Indianapolis and wants to visit her mom in Lima. She has been meaning to go to a chiropractor in Dayton, so she is
ella [17]

Answer: 44 miles

WORKINGS

Given,
The distance between Indianapolis and Lima, IL = 173 miles
The distance between Indianapolis and Dayton, ID = 165 miles
The distance between Dayton and Lima, DL is unknown

Since there are straight roads connecting the three cities, the connection between them form a right angles triangle.

The right angle is at Dayton
The hypotenuse is the distance between Indianapolis and Lima, IL

Therefore IL^2 = ID^2 + DL^2
173^2 = 165^2 + DL^2
DL^2 = 173^2 – 165^2
DL^2 = 29929 – 27225
DL^2 = 2704
DL = 52 miles

Therefore, The distance between Dayton and Lima, DL = 52 miles

The question is asking how many more miles would Meg drive if she stopped in Dayton first than if she drove directly to Lima.

That is, Distance of Indianapolis to Dayton + Distance of Dayton to Lima – Direct distance of Indianapolis to Lima
That is, ID + DL – IL
= 165 miles + 52 miles – 173 miles
= 217 miles – 173 miles
= 44 miles

Therefore, Meg would drive 44 more miles if she stopped in Dayton first than if she drove directly to Lima.
7 0
2 years ago
PLEASE!! For 22 points!!
daser333 [38]

Answer:

y = 3/5x + 3/5.

Step-by-step explanation:

the /'s are division symbols.              3            3

                                                  y =     _   +       _

                                                           5            5

5 0
2 years ago
A circular swimming pool has a diameter of the 26 feet.
kherson [118]
Hey there! :)

The formula for finding area of circles is: π · r²

<em>Remember that radius is half the diameter. To find radius when the diameter is given, divide by 2</em>

d = 26

26 ÷ 2 = 13
_____________________________________________________________

π · r²

r = 13
13² = 13 × 13 = 169

169 × 3.14 = 530.66 = 530.7

The area of the swimming pool is 530.7 ft²

Hope this helps :)
7 0
3 years ago
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