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77julia77 [94]
3 years ago
7

This is timed please help

Mathematics
2 answers:
Naya [18.7K]3 years ago
7 0
B. All real numbers greater than -1
lana66690 [7]3 years ago
3 0

Answer:

B.) All Real numbers greater than -1

<em><u>Unit Test Answers: For a 92%</u></em>

<em>**Go to question number 18 for the answer!**</em>

( Marking me brainliest would be great)

1.) B -3/2

2.)A -9

3.) B- b>0 and b\neq 1

4.)A

5.) D all real numbers greater than 3

6.)D 110Db

7.)C 5

8.)D 80

9.)B 3 times louder

10.)D

11.)A y<0

12.)A

13.)B

14.)D x=95

15.)B

16.)C x=-4

17.)B x=4

18.)B - All real numbers greather than -1

19.)A - Approximately x=0.46

20.)C 1/4

21.)D - 4logx + 1/2 log12 (x^2-2)- 5log 12 (x+1)

22.) C 1.5

23.)A -1

24.)D Translate each point 3 units to the left

25.)D 1.796

<u>I got a total of 92% which is a total of 23/25 two are wrong.</u>

It's a great grade !

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Zinaida [17]
$25.75 is how much money she saved up each week
5 0
3 years ago
What is the gcf of of -9y^2 + 6y
Valentin [98]

Answer:

3y

Step-by-step explanation:

First find the factors of the terms.  You need to then figure out how many factors match.

-9y² = -1 · 3 · 3 · y · y

6y = 2 · 3 · y

3y is the greatest common factor.

5 0
3 years ago
Can someone please answer this please and explain
Blababa [14]

Answer:

12  3  0  3  12

Step-by-step explanation:

Just plug in each value in the table in as x so when you plug in -2 that would be 3(-2)^2.  -2x-2=4. 4x3=12. :)

4 0
3 years ago
Read 2 more answers
A package of 5 crackers contains 205 Calories. How many Calories are in one cracker using a double number line
natulia [17]

Answer:

Step-by-step explanation:

since there are 205 calories in 5 crackers we can represent this as

205/5

we need to find how many calories are in one cracker, so lets take "x" as the # of calories in 1 cracker

so

\frac{x}{1} =\frac{205}{5}

cross multiply

5x=205

divide by 5 on both sides

x=41

41 calories in 1 cracker

Number line:

7 0
3 years ago
Help meeeeeeeeeeeeeee!!!!!!​
koban [17]

Answer:

2x+3=9

2x=6

x=3

3w-1=14

3w=15

w=5

7y+2=30

7y=28

y=4

5x+20=35

5x=15

x=3

6c-12=48

6c=60

c=10

8m-4=20

8m=24

m=3

7w+13=90

7w=77

w=11

12p-18=30

12p=48

p=4

9w-5=67

9w=72

w=8

10a+40=100

10a=60

a=6

9x-24=84

9x=108

x=12

7w+1=1

7w=0

w=0

your welcome

8 0
3 years ago
Read 2 more answers
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