What does (p + 7(-2) Equal To?

babymother [125]

Answer:

Third choice from the top is the one you want

Step-by-step explanation:

This whole concept relies on the fact that if the index of a radical exactly matches the power under the radical, both the radical and the power cancel each other out. For example:

$\sqrt[6]{x^6} =x$ and another example:

$\sqrt[12]{2^{12}}=2$

Let's take this step by step. First we will rewrite both the numerator and the denominator in rational exponential equivalencies:

$\frac{\sqrt[4]{6} }{\sqrt[3]{2} }=\frac{6^{\frac{1}{4} }}{2^{\frac{1}{3} }}$

In order to do anything with this, we need to make the index (ie. the denominators of each of those rational exponents) the same number. The LCM of 3 and 4 is 12. So we rewrite as

$\frac{6^{\frac{3}{12} }}{2^{\frac{4}{12} }}$

Now we will put it back into radical form so we can rationalize the denominator:

$\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }$

In order to rationalize the denominator, we need the power on the 2 to be a 12. Right now it's a 4, so we are "missing" 8. The rule for multiplying like bases is that you add the exponents. Therefore,

$2^4*2^8=2^{12}$

We will rationalize by multiplying in a unit multiplier equal to 1 in the form of

$\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }$

That looks like this:

$\frac{\sqrt[12]{6^3} }{\sqrt[12]{2^4} }*\frac{\sqrt[12]{2^8} }{\sqrt[12]{2^8} }$

This simplifies down to

$\frac{\sqrt[12]{216*256} }{\sqrt[12]{2^{12}} }$

Since the index and the power on the 2 are both 12, they cancel each other out leaving us with just a 2! Doing the multiplication of those 2 numbers in the numerator gives us, as a final answer:

$\frac{\sqrt[12]{55296} }{2}$

Phew!!!

4 0

4 years ago

Can you please help with this

Ksivusya [100]

First you want to turn both fractions into improper fractions. So 1 4/7 would now be 11/7 because 1 x 7 + 4 is 11. And -1 4/8 will now be -12/8 because 1 x 8 + 4 is 12. Now you must find the common denominator. 8 x 7 is equal to 56 so the common denominator is 56. So now we are adding 11/56 + (-12/56). 11 plus 12 is 23. So we have 23/56. 23 can go into 56 two times because 23 x 2 = 46. There is 10 left over so our final answer is -2 10/56. In simplest form our answer would be -2 5/28

4 0

3 years ago

please answer this question fast and please show all your work because I am locking for how can you do it please

inysia [295]

Option C is the correct values of the relationship between the number of cakes the baker makes and the number of bags of flour uses.

Solution:

Option A: Ratio of cakes baked to bags of flour used

$$\frac{9}{4}, \frac{18}{6}=\frac{3}{1} \text { and } \frac{27}{9}=\frac{3}{1}$

Here the ratios are not same.

So, this option is not true.

Option B: Ratio of cakes baked to bags of flour used

$$\frac{6}{2}=\frac{3}{1}, \frac{12}{4}=\frac{3}{1} \text { and } \frac{18}{6}=\frac{3}{1}$

Here the ratios are same.

So, this option is true.

Option C: Ratio of cakes baked to bags of flour used

$$\frac{4}{9}, \frac{6}{18}=\frac{1}{3} \text { and } \frac{9}{17}$

Here the ratios are not same.

So, this option is not true.

Option D: In this table cakes baked is 6 and the bags of flour is 18.

But a baker made 18 cakes using 6 bags of flour.

So, this option is not true.

Hence option C is the correct values of relationship between the number of cakes the baker makes and the number of bags of flour uses.

6 0

3 years ago

HELPP PLEASE GIVE EVIDENCE ni

STALIN [3.7K]

Step-by-step explanation:

The value of k in the equation g(x) = f(x) + k comes out to be 8.

How the vertical shifting of a graph takes place?

If the graph of a function f(x) is shifted vertically by k units, f(x) becomes f(x)+k.

From the diagram, we can say that graph of f(x) has been shifted vertically by 8 units

If we shift f(x) vertically by 8 units f(x) becomes f(x)+8 and also coincides with the graph of g(x).

So, g(x) = f(x) + 8........(1)

Comparing (1) and g(x) = f(x) + k, we get k=8.

Hence, the value of k in the equation g(x) = f(x) + k comes out to be 8.

6 0

3 years ago

if trangle pqr is translated 4 units to the right to form triangle p'q'r' how are the values on the orderd pairs affected by the

Vesna [10]

Answer:

The x-coordinate of each point will increase by 4.

Step-by-step explanation:

So Triangle PQR is being translated 4 units to the <em>right</em>. Since we are going to the <em>right</em>, this is a shift on the x-coordinate.

And since we're going 4 units, every x-coordinate is going to be added by 4.

In other words, if we have:

$A(x,y)$

Then the new coordinate, A', is:

$A(x,y)\rightarrow A' (x+4,y)$

So, let's find the new coordinates of each point.

Point P is (-5,6). So:

$P(-5,6)\rightarrow P'(-5+4,6)=P'(-1,6)$

The new Point P is at (-1,6).

Point Q is at (2,6). So:

$Q(2,6)\rightarrow Q'(2+4,6)=Q'(6,6)$

The new Point Q would be at (6,6).

And Point R is at (-3,2). So:

$R(-3,2)\rightarrow R(-3+4,2)=R(1,2)$

The new Point R is at (1,2).

And we're done!

5 0

3 years ago

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