What is the volume of the following rectangular prism?

Find the asymptotes of the hyperbola. (enter your answers as a comma-separated list of equations.) y=2x,y=−2x

Nastasia [14]

The answer to this question is <span>y=2x, y=−2x.</span>

8 0

3 years ago

A grading machine can grade 96 multiple

weqwewe [10]

Answer:

6.25 minutes or 375 seconds

Step-by-step explanation:

We can solve the following problem through the Proportion method.

Here,

we may take the time taken by the machine as x

$96 : 2 : : 300 : x\\96x= 2 *300\\96x=600\\x=600/96\\x=6.25\ minutes$

8 0

4 years ago

BEST ANSWER GETS BRAINLIEST!!! PLEASE HELP

Ksenya-84 [330]

The answer is 3X + 12 because in he distributive property you must multiply both the 3X and the 4 by 3

3x1=3 hence the 3X

and 3x4 = 12 <span />

8 0

3 years ago

Un metro cúbico equivale a 1000 litros de capacidad y un decímetro cúbico a un litro ¿Cuántos litros cabrán en una piscina de 12

Airida [17]

Answer:

12,500 liters

Step-by-step explanation:

Given that

One cubic meter = 1000 liters

One cubic decimeter = 1 liter

We need to find out the number of liters fit in a 12.5 cubic meter

So

As it is mentioned that

One cubic meter = 1000 liters

So for 12.5 cubic meter

The number of liters would be

= 1000 × 12.5

= 12,500 liters

3 0

3 years ago

Need help asap important! thanks so much!

a_sh-v [17]

Answer:

You would have $343.37 at the end of the 2 years.

Step-by-step explanation:

Interest earned is like bonus money the bank pays you just for keeping money

$\mathrm{Compund\:Interest\:Formula}:\quad A = P { \left( 1+ \dfrac{ r }{ n } \right) }^{ nt }$

P: the starting balance of the account (also called initial deposit, or principal)

A: the new balance in the account after N years.

t: the number of years or time

r: the interest rate, (in decimal form)

n: the number of times the interest is compounded each year.

Annually = each year = 1

P =$300, r = 7%, t = 2, n = 1, A = ?

Substitute the numbers into the "Compound Interest Formula".

$A = 300 { \left( 1+ \dfrac{ 0.07 }{ 1 } \right) }^{ 1 \times 2 }$

$\mathrm{Anything\:divided\:by\:1\:gives\:itself}$

$A = 300 { \left( 1+0.07 \right) }^{ 1 \times 2 }$

$\mathrm{Add\:1\:and\:0.07\:to\:get\:1.07}$

$A = 300 \times { 1.07 }^{ 1 \times 2 }$

$\mathrm{Multiply\:1\:and\:2\:to\:get\:2}$

$A = 300 \times { 1.07 }^{ 2 }$

$\mathrm{Calculate\:1.07\:to\:the\:power\:of\:2\:and\:get\:1.1449}$

$A = 300 \times 1.1449$

$\mathrm{Multiply\:300\:and\:1.1449\:to\:get\:343.47}$

$A = 343.47$

So you would have $343.37 at the end of the 2 years.

Look at the chart

$\mathrm{Year}\quad \mathrm{Year\: Interest}\quad \mathrm{Total\:Interest}\quad \mathrm{Balance}\\\quad1\quad\quad\quad $21.00\quad\quad\quad\quad $21.00\quad\quad\quad\quad $321.00\\\quad2\quad\quad\quad $22.47\quad\quad\quad\quad $43.47\quad\quad\quad\quad $343.47$

8 0

3 years ago