Moles Li = 3.50 g / 6.941 g/mol= 0.504
the ratio between Li and N2 is 6 : 1
moles N2 required = 0.504 /6=0.0840
we have 3.50 g / 28.0134 g/mol=0.125 moles of N2 so N2 is in excess
the ratio between Li and Li3N is 6 : 2
moles Li3N = 0.504 x 2 /6=0.168
mass Li3N = 0.168 mol x 34.8297 g/mol=5.85 g
2 C2H6 + 7 O2 ➡️ 4 CO2 + 6 H2O
Its the molecules have 20 electrons so the bear fainted.
Answer:15 +18
Explanation:15 fuel +18 oxygen + 33 cd