Answer:
-1.82 °C
Explanation:
Step 1: Given data
- Mass of NaCl (solute): 33.9 g
- Mass of water (solvent): 578 g = 0.578 kg
- Freezing point depression constant for water (Kb): -1.82 °C/m
Step 2: Calculate the molality of the solution
We will use the following expression.
m = mass of solute / molar mass of solute × kg of solvent
m = 33.9 g / 58.44 g/mol × 0.578 kg
m = 1.00 m
Step 3: Calculate the freezing point depression (ΔT)
The freezing point depression is a colligative property that, for a non-dissociated solute, can be calculated using the following expression:
ΔT = Kb × m
ΔT = -1.82 °C/m × 1.00 m
ΔT = -1.82 °C
Propene is the unsaturated compound.
Explanation:
In the presence of sulphuric acid (H₂SO₄), propanol will eliminate one water molecule (H₂O) to form propene, which is the unsaturated compound.
You may find the chemical reaction with the chemical diagrams of the compounds in the attached picture.
Learn more about:
dehydration of alcohols
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Answer:
Protium
Explanation:
Isotopes -
For some elements , there are various forms possible , which have different number of neutron and same number of protons , are referred to as the isotopes .
The three isotopes possible for the element hydrogen are -
Protium , Deuterium and Tritium .
Where ,
- Protium has one electron , one proton and zero neutron.
- Deuterium has one electron , one proton and one neutron.
- Tritium has one electron , one proton and two neutron.
The most abundant isotope observed is Protium , with 99.98% abundance.
Answer:1kg. Explanation: ( b is the symbol for molality, and molality is the number of moles of solute per kilogram of solvent). b=nm. 0.5=0.5m. m=1kg.
Explanation:
