<span><span>Atomic number36,</span><span>Atomic mass<span>83.80 g.mol -1,</span></span><span>Density<span>3.73 10-3 g.cm-3 at 20°C,</span></span><span>Melting point- 157 °C,</span><span>Boiling point<span>- 153° C</span></span></span>
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You have OH- conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is 4 : 6 = 2:3
So, for 2.3 ✕ 10−6 m OH-
[Cu2+] =

Psolution = X · PH_20
= 0.966 · 31.8 torr
= 30.7 torr
What is the percent composition by mass of oxygen in magnesium oxide, MgO?
Answer: 39.7 percent
Vs = 1.0 mL = 0.001 L
c((NH4)2CO3) = <span>0.02 M
n(</span>(NH4)2CO3) = ?
For the purpose, here we will use the next equation:
c=n/V ⇒ n=cxV
n((NH4)2CO3) = 0.02M x 0.001L
n((NH4)2CO3) = 2x10⁻⁵ mole of (NH4)2CO3 is presented in the solution