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icang [17]
3 years ago
15

What is the empirical formula of a compound containing 12 g of carbon, 2 g of hydrogen, and 16 g of oxygen only

Chemistry
1 answer:
Hoochie [10]3 years ago
7 0

Answer:

The empirical formula=CHO. To explain it is C1H1O1 but we don't put the one that's why it is CHO

Explanation:

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PLZ HELP IT BEING TIMED!!!!!! PLZ ANSWER!!!!!
Wittaler [7]

Answer:

YIKES. a bit late. Answers include 1, 2, 3

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6 0
3 years ago
What happens to the ions when the drain is turned off? please help :] ❤️
kkurt [141]

Answer:

In a long channel MOSFET, the width of the pinch-off region is assumed small relative to the length of the channel. Thus, neither the length nor the voltage across the inversion layer change beyond the pinch-off, resulting in a drain current independent of drain bias. Consequently, the drain current saturates.

Explanation:

pls Mark my answer in brainlist and follow me

5 0
3 years ago
Explain why the production of a gas in this experiment is or is not different from the formation of water vapor in the heating c
den301095 [7]

The production of a gas is different because unlike the heating curve, there was no heat applied to this experiment, and the experiment was a chemical reaction.

<h3>What is a Heating curve?</h3>

This shows the relationship between the temperature of the heating system and the air temperature in the outer environment.

The chemical reaction emitted heat as against the other which involved heat application which is why water formation in this curve was different.

Read more about Heating curve here brainly.com/question/14094062

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6 0
2 years ago
How many significant figures does 602.060 have. what is its precision
ryzh [129]

That number has 6 significant numbers. It's precision would be 602.

Hope it helped.  

4 0
3 years ago
Calculate the concentration of chloride ions when 100.0 mL of 0.233 M sodium chloride is mixed with 250.0 mL of 0.150 M calcium
serg [7]
The dissociation of both salts NaCl and CaCl₂ are as follows;
NaCl --> Na⁺ + Cl⁻

CaCl₂ --> Ca²⁺ + 2Cl⁻

the molar ratio of NaCl to Cl⁻ is 1:1
therefore number of NaCl moles is equal to number of Cl⁻ ions dissociated from NaCl
then number of Cl⁻ ion moles - 0.233 mol/L x 0.1000 L = 0.0233 mol

molar ratio of CaCl₂ to Cl⁻ ions is 1:2
1 mol of CaCl₂ gives out 2 mol of Cl⁻ ions.
number of CaCl₂ moles - 0.150 mol/L x 0.2500 L  = 0.0375 mol 
then the number of Cl⁻ ion moles - 0.0375 x 2 = 0.0750 

total number of Cl⁻ ion moles = 0.0233 mol + 0.0750 mol = 0.0983 mol
volume of solution - 100.0 + 250.0 = 350.0 mL 

concentration of Cl⁻ = 0.0983 mol / 0.3500 L = 0.281 M
concentration of Cl⁻⁻ is 0.281 M 
4 0
3 years ago
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