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tangare [24]
3 years ago
10

A 37.2-g sample of lead (Pb) pellets at 20°C is mixed with a 62.7-g sample of lead pellets at the same temperature. What are th

e final mass, temperature, and density of the combined sample? The density of Pb at 200C is 11.35 g/cm^3.
Chemistry
1 answer:
Vesnalui [34]3 years ago
8 0

Answer:

Mass of sample is 99.9 g, density of ample is 11.35 g/cm^{3} and temperature of sample is 20^{0}\textrm{C}

Explanation:

Mass is an additive property. Therefore mass of combined sample is summation of masses of two pellets.

Mass of combined sample = (37.2+62.7) g = 99.9 g

Density is an intensive property. Therefore density of combined sample of lead will be same as with density of Pb.

Density of combined sample = 11.35 g/cm^{3}

Temperature is an intensive property. Therefore temperature of combined sample of lead will be same as with individual pellets.

temperature of combined sample = 20^{0}\textrm{C}

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A NaOH solution is standardized using the monoprotic primary standard potassium hydrogen phthalate, KHP (204.22 g/mol.) If 0.698
kakasveta [241]

Answer:

0.07789 M is the sodium hydroxide concentration.

Explanation:

Mass of potassium hydrogen phthalate = 0.6986 g

Molar mass of potassium hydrogen phthalate = 204.22 g/mol

Moles of  potassium hydrogen phthalate = \frac{0.6986 g}{204.22 g/mol}=0.003421 mol

NaOH+KHP\rightarrow NaKP+H_2O

According to reaction , 1 mole og KHp reactswith 1 mole of NaOH , then 0.003421 moles of KHp will react with :

\frac{1}{1}\times 0.003421 mol=0.003421 mol

Moles of NaOH = 0.003421 mole

Volume of NaOH solution = 43.92 ml = 0.04392 L ( 1 mL = 0.001L)

Concentration=\frac{Moles}{Volume(L)}

Concentration of NaOH :

\frac{0.003421 mol}{0.04392 L}=0.07789 M

0.07789 M is the sodium hydroxide concentration.

5 0
3 years ago
If 35.50 cm3 of a NaOH solution are required for the complete neutralization of a 25.00cm3 sample of 0.200mol dm-3 H2SO4, what i
Morgarella [4.7K]
In this question, you are given the NaOH volume but asked for concentration. 
Don't forget that for every 1 mol of NaOH there will be 1 mol OH- ion, but for every 1 mol of H2SO4 there will be 2 mol of H- ion.
To neutralize you need the same amount of OH- and H+, so the equation should be:

OH-= H+
<span>35.50cm3 * x*1= 25cm3* 0.2mol/dm3 *2
</span>x= 10/35.5 mol/dm3= 0.2816/dm3
6 0
3 years ago
A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t
kotegsom [21]

<u>Given:</u>

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

<u>To determine:</u>

The enthalpy of formation of AgCl(s)

<u>Explanation:</u>

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol


6 0
3 years ago
Read 2 more answers
Source from which organisms benefit
vampirchik [111]

Answer:

a ecosystem

Explanation:

7 0
4 years ago
3. Ca(OH)2 + 2HCI = Cacl. + 2HO
Sergeu [11.5K]

Answer:

https://download.cnet.com/1-Click-Answers/3000-2378_4-10060189.html

Explanation:

4 0
3 years ago
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