A triangle has sides of lengths 6 and 9. What value could the length of the third side?

2 answers:

8 0

Any number except one greater or equal to 15 or 0.

No one sides can be greater than or equal to the sum of the other 2 sides.

For example, side length 8 would be fine

laiz [17]3 years ago

3 0

The answer is 23

Hope this helped. Give support by thanking me and giving brainliest

You might be interested in

What is the value of f(−1)f(−1) when f(x)=2x 2 ? enter your answer in the box. f(−1)=

sergiy2304 [10]

I hope this helps you

x= -1

f (-1)= 2. (-1)^2

f (-1)= 2.1

f (-1)= 2

6 0

3 years ago

Plz help me I've been dealing with this for 4 days.

Sloan [31]

Step-by-step explanation:

(qvp)5=4-5=54643434346

3 0

3 years ago

A gourmet candy company charges the

MrRissso [65]

I’m pretty sure it’s C. because half of 12 is 6 so if they’re buying a pound and a half it would be 12+6, which is 18

8 0

2 years ago

For the standard form of two billion three Hundred fifty thousand four Danielle wrote 2,350,400,000 what error did she make what

Leona [35]

I believe the correct answer is 2,300,500,004

7 0

3 years ago

How would I solve this Rational Equation? <br><br>Solve for all values of x.

Nesterboy [21]

9514 1404 393

Answer:

x = 4

Step-by-step explanation:

I like to put these in the form f(x) = 0. We can do that by subtracting the right side. Common factors can be cancelled from numerator and denominator, provided they are not zero.

$\dfrac{7}{x+3}+\dfrac{3}{x-3}-\dfrac{x}{x-3}=0\\\\ \dfrac{7(x-3)+(x+3)(3-x)}{(x+3)(x-3)}=0\\\\\dfrac{(x-3)(4-x)}{(x-3)(x+3)}=0\\\\ \dfrac{4-x}{x+3}=0\qquad x\ne3\\\\x=4 \qquad\text{equate the numerator to zero, add $x$}$

_____

If you leave the numerator as (x-3)(4-x), then there are two values of x that make it zero. Because x=3 makes the equation "undefined", it cannot be considered to be a solution.

4 0

3 years ago