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3 years ago

A triangle has sides of lengths 6 and 9. What value could the length of the third side?

2 answers:

8 0

Any number except one greater or equal to 15 or 0.

No one sides can be greater than or equal to the sum of the other 2 sides.

For example, side length 8 would be fine

laiz [17]3 years ago

3 0

The answer is 23

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3 years ago

How to do the problem

trapecia [35]

Step-by-step explanation:

$g(0.5) = 2 \\ \\ h(x) = g(x).f(x) \\ \therefore \: h(2) = g(2).f(2) \\ \therefore \: h(2) = 5 \times 2\\ \therefore \: h(2) = 10\\ \\ \\ j(x) = g(x) - f(x) \\ \therefore \: j(4) = g(4) - f(4) \\ \therefore \: j(4) = 9 - 8\\ \therefore \: j(4) = 1\\ \\ \\$

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3 years ago

Suppose X has an exponential distribution with mean equal to 23. Determine the following:

e-lub [12.9K]

Answer:

a) P(X > 10) = 0.6473

b) P(X > 20) = 0.4190

c) P(X < 30) = 0.7288

d) x = 68.87

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \mu e^{-\mu x}$

In which $\mu = \frac{1}{m}$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\mu x}$

The probability of finding a value higher than x is:

$P(X > x) = 1 - P(X \leq x) = 1 - (1 - e^{-\mu x}) = e^{-\mu x}$

Mean equal to 23.

This means that $m = 23, \mu = \frac{1}{23} = 0.0435$

(a) P(X >10)

$P(X > 10) = e^{-0.0435*10} = 0.6473$

P(X > 10) = 0.6473

(b) P(X >20)

$P(X > 20) = e^{-0.0435*20} = 0.4190$

P(X > 20) = 0.4190

(c) P(X <30)

$P(X \leq 30) = 1 - e^{-0.0435*30} = 0.7288$

P(X < 30) = 0.7288

(d) Find the value of x such that P(X > x) = 0.05

$P(X > x) = e^{-\mu x}$

$0.05 = e^{-0.0435x}$

$\ln{e^{-0.0435x}} = \ln{0.05}$

$-0.0435x = \ln{0.05}$

$x = -\frac{\ln{0.05}}{0.0435}$

$x = 68.87$

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3 years ago

The temperature outside was 60 degrees when Sarah woke up. By noon, it had increased to 75 degrees. Find the percent increase in

DochEvi [55]

Temp1 = 60
Temp2 = 75
Temp2 - Temp1 = 15

Difference = (Temp2 - Temp1) / Temp1
Difference = 15 / 60 = 1 / 4 = 0.25
Percentage difference = difference * 100% = 0.25 * 100% = 25%

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3 years ago