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Nimfa-mama [501]
3 years ago
5

1. Find the product. Your answer should be in simplest form.

Mathematics
1 answer:
svp [43]3 years ago
3 0

Answer:

1) 24

2) 21/2 = 10 1/2

3) 2/5

Step-by-step explanation:

1) We have 2 2/3 * 9, to solve this we have to know that in multiplications we multiply the numerator from the first fraction times the numerator from the second fraction, and the denominators are multiplied too.

We also know that 2 2/3 = 8/3, because we multiply 2 times the denominator and then we add that result plus the numerator.

So now we have:

8/3 * 9 = 72/3 = 24

2) We do the same thing than in problem 1.

We have -4 1/2 * -2 1/3, so first we change them:

-4 1/2 = -9/2 and -2 1/3 = -7/3, so we have:

-9/2 * -7/3 = 63/6 = 21/2 = 10 1/2

3) We have 1/3 ÷ 5/6, to divide we can flip the second fraction and just solve it as a multiplication:

1/3 * 6/5 = 6/15 = 2/5

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A bike shop marks up a hybrid bike from $200 to $330 and discounts a road bike from 330 to 200 by what you percent is the road b
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Answer:

39.39%

Step-by-step explanation:

There's a nice little formula that is used to find percentage change which works regardless of if it's an increase or decrease.

Percent~Change = |\frac{New~Value~-~Original~Value}{Original~Value}| * 100

1 - Understanding the equation

The '|'s which are surrounding the fraction are absolute value symbols in mathematics,

Absolute value means the positive value of anything inside

<u>Examples</u>:

| -8 | = 8

| 8 |  = 8

and

| -2 | = 2

| 2 |  = 2

the * 100 means you multiply (the * symbol means multiply) by 100.

We do this to get it into a percent.

3 - Assign numbers to the values from our equation

Original Value (What it changed from): 330

New Value (What it changed to): 200

3 - Plug in our values into our variables from our equationPercent~Change = |\frac{200-330}{330}| * 100 = |\frac{-130}{330}| = = |-0.39...| * 100 = 0.3939... *100 =

<em>Our percent change is 39.39%, and with our percent in which is discounted being the same, we have our answer.</em>

<em />

Hope this helps :)

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