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Paladinen [302]
3 years ago
5

Sam scored 43, 48, and 42 points on three tests. How many points should he get on the fourth test to get an average score of 50?

(1 point) 83 points 67 points 45.75 points 44.33 points

Mathematics
2 answers:
fomenos3 years ago
8 0

Answer:

Hi!! The answer is 44.33 I just took the test it`s 100% verified!

tatiyna3 years ago
6 0

So we know that an average is the sum of the scores divided by the number of scores that were added together. In this case we are going to be dealing with 4 tests. So let's say x is the score for our fourth test. We can create this equation:

\frac{x+43+48+42}{4}=50

So then we need to simplify the top:

\frac{x+133}{4}=50

Then multiply by 4 on both sides to get rid of the denominator:

x+133=200

Then solve for x:

x=67

So now we know that Sam needs to score a 67 on the fourth test to have an average score of 50.

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The carton has a volume of 1,000 unit cubes.

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Hi please somebody help me with this equation with explanation thank you
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Solve the equation. n+34=14
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Answer:

n = -20

Step-by-step explanation:

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3 years ago
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The time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a
AlekseyPX

Answer:

The time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

Step-by-step explanation:

We are given that the time for this event for boys in secondary school is known to possess a normal distribution with a mean of 460 seconds and a standard deviation of 40 seconds.

The fitness association wants to recognize the fastest 10% of the boys with certificates of recognition.

<u><em>Let X = time for this event for boys in secondary school</em></u>

SO, X ~ Normal(\mu=460,\sigma^{2} =40^{2})

The z-score probability distribution for normal distribution is given by;

                               Z = \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = mean time = 460 seconds

            \sigma = standard deviation = 40 seconds

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

<u>Now, it is given that the fitness association wants to recognize the fastest 10% of the boys with certificates of recognition, which means;</u>

       P(X > x) = 0.10   {where x is the required time which boy need to beat}

       P( \frac{X-\mu}{\sigma} > \frac{x-460}{40} ) = 0.10

        P(Z > \frac{x-460}{40} ) = 0.10

<em>So, the critical value of x in the z table which represents the top 10% of the area is given as 1.2816, that is;</em>

<em>                   </em>      \frac{x-460}{40} =1.2816

                         {x-460}{} =1.2816\times 40

<em>                           </em>x = 460 + 51.264 = <u>511.264 seconds</u>

Hence, the time that the boys need to beat in order to earn a certificate of recognition from the fitness association is 511.264 seconds.

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