Answer:
The reaction D has the value of ΔH°rxn equal to ΔH°f for the product.
Explanation:
The ΔH°f for product is equal to ΔH°rxn when the reagents are in their elemental state (ΔH°f = 0) and form one mole of product.
We have to find the reagents that are in their elemental state and that only form one mole of product:
A) 2Ca (s) + O₂ (g) → 2CaO (s)
The reagents are in their elemental state but the reaction forms two mole of product.
B) C₂H₂ (g) + H₂ (g) → C₂H₄ (g)
C₂H₂ (g) is not in its elemental state.
C) 2C (graphite) + O₂ (g) → 2CO (g)
Graphite and Oxygen are in their elemental state but the reaction forms two mole of product.
D) 3Mg (s) + N₂ (g) → Mg₃N₂ (s)
Magnesium and Nytrogen are in their elemental state and the reaction forms one mole of product.
E) C (diamond) + O₂ (g) → CO₂ (g)
Diamond is not in its elemental state.
The answer is C Nuclear Regulatory Commission
Explanation:
(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.
The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.
The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.
(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.
Answer:
Al(OH)- 4,
Explanation:
NaOH added to 0.010 M Al3+
The predominant species at equilibrium will be = Al(OH)- 4, and this because sodium hydroxide ( NaOH ) is a base will readily form a stable complex ion with aluminum ion like ( Al( OH ) - 4 . also the higher the Kf value the more stable the complex ion becomes and the more soluble Al(OH)3 becomes
hence the predominant species at equilibrium is : Al(OH)- 4,
It is an alkene: CnH2n (n=number of the atoms of carbon)
in ethylene there are two carbons so:
C2H4 just like the picture
