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Vlada [557]
3 years ago
8

Consider molecular, complete ionic, and net ionic equations.

Chemistry
1 answer:
8090 [49]3 years ago
3 0

Explanation:

(a) The molecular equations shows the equation in which all the species of the reactants and the products are in molecules and the net charge is zero.

The complete ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and are represented as ions.

The net ionic equations shows the equation in which all the species of the reactants and the products are in dissociated form and do not show the spectator ions which are same in the reactants and the products.

(b) If there is no spectator ions in the reaction, then the complete and the net ionic equations would be identical.

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wlad13 [49]

Answer:

B. wave 1 has a larger wavelength than wave 2

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Which metals have similar chemical properties? Check all that apply. barium beryllium rubidium radium titanium calcium platinum
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beryllium & calcium are the two in the same column or family

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Read 2 more answers
Nitrogen monoxide and oxygen, both colorless gases, form a red-brown gas when mixed. Nitrogen monoxide and oxygen are called the
daser333 [38]

Answer:

Nitrogen monoxide and oxygen are called the reactants

Explanation:

Step 1: Given data

Nitrogen monoxide = NO

Oxygen = O2

Step 2: Balanced equation

2NO + O2 → 2NO2

This means that 2 moles of NO will be consumed and and 1 mole of O2 to produce 2 moles of NO2

This means NO2 is the prodcut that is produced.

NO +O2 react with eachother, to form NO2

This means nitrogen monoxide (NO) and Oxygen (O2) are called the reactants.

5 0
3 years ago
If the forward reaction goes close to completion and has a high yield, what is the expected value of the equilibrium constant (k
Anna007 [38]
If the forward reaction goes close to completion and has a high yield, that means the concentration of products will be higher than the concentration of reactants. 

<span>So if the concentration of products is higher, Kc (equilibrium constant) will be greater than 1.
</span><span>
Recall the calculation for the equilibrium constant for reaction. Picture below might help you.</span>

8 0
3 years ago
Need help with chemistry question
luda_lava [24]

Answer:

See explanation

Explanation:

In this case, we have to check two variables:

1) The leaving group

2) The carbon bonded to the leaving group.

Let's check one by one:

<u>2-chloro-3-methylbutane</u>

<u />

In this molecule, the leaving group is "Cl", the carbon bonded to the leaving group has two neighbors. Therefore, we have a <u>secondary substrate.</u>

<u>1-phenylpropan-1-ol</u>

<u />

In this molecule, the leaving group is "OH", the carbon bonded to the hydroxyl group has two neighbors also. So, we have a <u>secondary substrate.</u>

<u>(E)-pent-3-en-2-yl 4-methylbenzenesulfonate</u>

<u />

In this case, the leaving group is "OTs" (Tosylate), the carbon bonded to the tosylate group has as a neighbor a double bond. Therefore, we have an <u>allylic substrate.</u>

<u>3a-bromooctahydro-1H-indene</u>

<u />

In this molecule, the leaving group is "Br", the carbon bonded to the bromine has three neighbors. So, we have a <u>tertiary substrate.</u>

<u>1-iodo-3-methylbutane</u>

<u />

In this molecule, the leaving group is "I", the carbon bonded to the iodide has only one neighbor. So, we have a <u>primary substrate.</u>

<u />

See figure 1

I hope it helps!

<u />

4 0
3 years ago
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