<span>As particles travel in straight lines, their paths sometimes meet, and then they bounce apart with no gain or loss of energy. hope this help:)</span>
Answer:
Thallium absorbed 1069.645 J heat to reach to its melting point.
Explanation:
Specific heat capacity:
It is the amount of heat required to raise the temperature of one gram of substance by one degree.
Formula:
Q = m.c. ΔT
Q = amount of heat absorbed or released
m = mass of given substance
c = specific heat capacity of substance
ΔT = change in temperature
Given data:
Mass of thallium = 32.9 g
specific heat capacity of thallium = 0.128 j/g. °C
Initial temperature = 49 °C
Final temperature = 303 °C
Solution:
Change in temperature = T₂- T₁
ΔT = 303 °C - 49 °C = 254 °C
Formula:
Q = m.c. ΔT
Q = 32.9 g ×0.128 j/g. °C × 254 °C
Q = 1069.645 J
Thallium absorbed 1069.645 J heat to reach to its melting point.
True. 1mL equals 1x10⁻³L so to convert mL into L you have to move the decimal point over 3 places to the left.
I hope this helps. Let me know in the comments if anything is unclear.
Answer:
76%
Explanation:
The lab grade of the student is made of report sheets, lab exams and lab quizzes with different weights for each score. To find the lab grade we need to multiply each score with respective weight. He has 86% in the report sheet which has 35% weight, 66% in the lab exam which have 35% weight, and 76% in the quizzes which have 30% weight. The score will be:
86%*35% + 66%*35% + 76%*30%= 76%
His score for the lab grade will be 76%