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nikdorinn [45]
3 years ago
13

The element Oxygen, O, is an example of which of the following?

Chemistry
2 answers:
PtichkaEL [24]3 years ago
8 0
It's a example of a atom c
nikitadnepr [17]3 years ago
4 0

It’s the example of C atom I just did this on my test

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How many molecules of copper sulfate are needed to produce 5.0×1024 molecules of sodium sulfate?
lubasha [3.4K]

Answer:

5.0 × 10²⁴ molecules

Explanation:

Step 1: Write the balanced double displacement reaction

2 NaOH + CuSO₄ ⇒ Na₂SO₄ + Cu(OH)₂

Step 2: Calculate the moles corresponding to 5.0 × 10²⁴ molecules of Na₂SO₄

We will use Avogadro's number: there are 6.02 × 10²³ molecules in 1 mole of molecules.

5.0 × 10²⁴ molecule × 1 mol/6.02 × 10²³ molecule = 8.3 mol

Step 3: Calculate the moles of CuSO₄ required to produce 8.3 moles of Na₂SO₄

The molar ratio of CuSO₄ to Na₂SO₄ is 1:1. The moles of CuSO₄ required are 1/1 × 8.3 mol = 8.3 mol.

Step 4: Calculate the molecules corresponding to 8.3 moles of CuSO₄

We will use Avogadro's number.

8.3 mol × 6.02 × 10²³ molecule/1 mol = 5.0 × 10²⁴ molecule

4 0
3 years ago
. Use arrows to show electron pairing in the 4s and 3d orbitals of the following:<br> Nickel
EastWind [94]

Answer:

See diagram and explanation

Explanation:

Nickel belongs to group 10 in the periodic table. Its valence orbitals are the 4s2 3d8 orbitals. Nickel has two unpaired electrons in ground state as we can see from the image attached.

The pairing pattern for nickel is also shown in the image.

5 0
3 years ago
The most common source of copper (cu) is the mineral chalcopyrite (cufes2). how many kilograms of chalcopyrite must be mined to
tigry1 [53]

Answer : 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.

Solution : Given,

Mass of Cu = 300 g

Molar mass of Cu = 63.546 g/mole

Molar mass of CuFeS_2 = 183.511 g/mole

  • First we have to calculate the moles of Cu.

\text{ Moles of Cu}=\frac{\text{ Given mass of Cu}}{\text{ Molar mass of Cu}}= \frac{300g}{63.546g/mole}=4.7209moles

The moles of Cu = 4.7209 moles

From the given chemical formula, CuFeS_2 we conclude that the each mole of compound contain one mole of Cu.

So, The moles of Cu = Moles of CuFeS_2 = 4.4209 moles

  • Now we have to calculate the mass of CuFeS_2.

Mass of CuFeS_2 = Moles of CuFeS_2 × Molar mass of CuFeS_2 = 4.4209 moles × 183.511 g/mole = 866.337 g

Mass of CuFeS_2 = 866.337 g = 0.8663 Kg         (1 Kg = 1000 g)

Therefore, 0.8663 Kg of chalcopyrite must be mined to obtained 300 g of pure Cu.


3 0
3 years ago
Question 4 (1 point) Unless otherwise instructed. You may use the per Problems and Solutions book for this question carbonate (C
stepladder [879]

Answer:

sry i need points

don't be mad

Explanation:

4 0
3 years ago
54. Given the density of lead to be 11.4 g/cm' and a sample mass of 32 g what is the volume of this sample of
poizon [28]
54/2x32 g = 3 11.4g The value is multiplied by the giving 54
4 0
3 years ago
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