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nikdorinn [45]
3 years ago
13

The element Oxygen, O, is an example of which of the following?

Chemistry
2 answers:
PtichkaEL [24]3 years ago
8 0
It's a example of a atom c
nikitadnepr [17]3 years ago
4 0

It’s the example of C atom I just did this on my test

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Which is the molar mass of H2O?
Svetllana [295]
H=(2x1.008)=2.016
O= 15.999

15.999
+ 2.016
______
18.015 g/mol :)

3 0
3 years ago
Read 2 more answers
HRISTINA HERRERA: Attempt 1
Lunna [17]

Answer:

7.5 g of hydrogen gas reacts with 50.0 g oxygen gas to form 57.5 g of water.

Explanation:

Here we have the check if the mass of the reactants is equal to the mass of the products.

Reactants

7.5+50=57.5\ \text{g}

Products

57.5\ \text{g}

The data is consistent with the law of conservation of matter.

Reactants

50+243=293\ \text{g}

Products

206+97=303\ \text{g}

The data is not consistent with the law of conservation of matter.

Reactant

17.7+34.7=52.4\ \text{g}

Products

62.4\ \text{g}

The data is not consistent with the law of conservation of matter.

Only the first data is consistent with the law of conservation of matter.

8 0
3 years ago
a culinary student fills a 40ml container with 37.2 grams of vegetable oil.What is the density of the oil
Lynna [10]

Answer:

<h2>0.93 g/mL</h2>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 37.2 g

volume = 40 mL

We have

density =  \frac{37.2}{40}  \\  = 0.93

We have the final answer as

<h3>0.93 g/mL</h3>

Hope this helps you

4 0
2 years ago
If 48 g of magnesium reacts with oxygen gas, how many grams of magnesium oxide will be formed according to the following equatio
Aloiza [94]

think it maybe 48 mg0 because there should be 2g magnesium in the word equation

4 0
3 years ago
Read 2 more answers
Consider that calcium metal reacts with oxygen gas in the air to form calcium oxide. suppose we react 7.43 mol calcium with 4.00
Natali [406]
The balanced chemical equation for the above reaction is as follows;
2Ca + O₂ --> 2CaO
stoichiometry of Ca to O₂ is 2:1
this means that 2 mol of Ca reacts with 1 mol of O₂.
If O₂ is the limiting reactant, 
4 mol of O₂ should react with (4x2) - 8 mol of Ca
however only 7.43 mol of Ca is present. Therefore Ca is the limiting reactant.
7.43 mol of Ca reacts with - 7.43/2 = 3.715 mol of O₂
therefore there's excess O₂₂ remaining after the reaction
Since Ca is the limiting reactant, it is fully used up in the reaction and there is no Ca remaining after the reaction is completed.


4 0
3 years ago
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